Hi there!
![3 {a}^{2} - 6a \: = 3a(a - 2)](https://tex.z-dn.net/?f=3%20%7Ba%7D%5E%7B2%7D%20%20-%206a%20%5C%3A%20%20%3D%203a%28a%20-%202%29)
We can see this by writing the factors as multipliers. We get the following:
![3a {}^{2} = 3 \times \: a \times a](https://tex.z-dn.net/?f=3a%20%7B%7D%5E%7B2%7D%20%20%3D%203%20%5Ctimes%20%5C%3A%20a%20%20%5Ctimes%20a)
![6a = 3 \times 2 \times a](https://tex.z-dn.net/?f=6a%20%3D%203%20%5Ctimes%202%20%5Ctimes%20a)
Now we can see that the terms that are in common are 3 and a, and therefore we can bring those outside the parenthesis.
Answer:
-45
Step-by-step explanation:
5 *-1 *-3= 15
4 *-3 *4= -48
3 *4 *-1=-12
15 -48 -12= -45
If 68 is a prime number, then the only factors it has are 1 and 68.
If it has any other factors besides 1 and 68, then it's NOT prime.
Right away, without any higher math, you can look at just the last digit
in 68 . The last digit is '8'. That tells you that '68' is an even number,
and THAT tells you that '2' must be one of its factors. So '68' is not a
prime number.
The factors of 68 are 1, 2, 4, 17, 34, and 68 .
68 has four more factors besides 1 and 68, so it's not a prime number.
Every calculation with multiple operations must abide to BODMAS (Brackets, Other, Divide, Multiple, Addition, Subtraction)
Thus we would multiple first, giving us 86138220. Then we would add giving us: 86145009
Answer:
100
Step-by-step explanation: