Answer:

Step-by-step explanation:
From the given figure it is clear that the stop board is a regular hexagon and ∠I is an exterior angle of the regular hexagon.
Exterior angle of a regular polygon with n sides 
In a regular hexagon number of sides: n =6
Exterior angle of a regular hexagon 
Since ∠I is an exterior angle of the regular hexagon, therefore,
.
Answer:Let =tan2
t
=
tan
x
2
, then cos=1−21+2
cos
x
=
1
−
t
2
1
+
t
2
and tan=21−2
tan
x
=
2
t
1
−
t
2
.
Now
1+21−2+21−2(1+)21−21+1−tan2
Step-by-step explanation:
Answer:
$3200
Step-by-step explanation:
The total area of land is 30 acre. Let x represent the area in acre that corn is planted and y represent the area in acre that wheat is planted. Therefore:
x + y = 30 (1)
Also, the farmer can spend at most $750 on seeds. Corn cost $15 per acre, maize cost $30 per acre. Hence:
15x + 30y ≤ 750 (2)
Also, x and y > 0
The profit is given by the function:
Profit = 100x + 110y
Graphing equation 1 and equation 2 and solving, we get the points:
(10, 20)
Hence the maximum profit is at:
Max profit = 100(10) + 110(20) = $3200
Answer:

Step-by-step explanation:
A = 30° and r = 12







.
Happy to help :)
I'll proceed by evaluating total length and surface area by scanned images. For measurements, I suggest to use winrhizo or any similar software. In this case the most important thing to think about is to use the appropiate acquisition parameters, I mean, to set a good resolution during scanning. Pixels of the aquired image should be smaller than root hairs diameter. Therefore, let me try to suggest you a good acquisition resolution. Making a quick research, it seems that hair root diameters range between 0,012 and 0,017 mm, so I suggest a resolution that will give a pixel dimension of 0,002 mm. Root hair diameters should be composed by 6-8 pixels, that is enough for winrhizo measurements. Resolution is measured in dpi, so in "dots/pixel per inch". A inch is 25,4 mm. We need pixels with a diameter of 0,002 mm, so in 25,4 mm we found 12700 pixels. That means 12700 dpi. It's a very high resolution, you need a good scanner and much space in your computer.