Hello from MrBillDoesMath!
Answer:
Limit does not exist.
Discussion:
The function 1/x has a vertical asymptote as x approaches 0 so
sin (pi/x) has no limit as x approaches 0. In fact, it oscillates wildly between -1 and 1 as x approaches 0. See attached graph of function
Thank you,
MrB
Have a good day people
Step-by-step explanation:
lcm 16 & 10 = 80
lcm j^8 & j^9 = j^9
lcm k^8 & k^4 = k^8
lcm m^5 & m^6 = m^6
answer is: 80j^9k^8m^6