An inequality where the difference between 2 and a number is at least negative 1 will be x - 2 ≥ -1.
<h3>What is the inequality?</h3>
The first part of the inequality is that there is a difference between a number and 2.
Assuming that number is 2, the first part is:
x - 2
The result of this subtraction at least negative 1. When a number is at least a number, it means that it is either that number or larger.
So the total inequality is:
x - 2 ≥ -1
Find out more on inequalities at brainly.com/question/16914953.
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Answer:
The fifth root is 2[cos(56°) + i sin(56°)]
Step-by-step explanation:
* To solve this problem we must revise De Moiver's rule
- In the complex number with polar form
∵ z = r(cosФ + i sinФ)
∴ z^n = r^n(cos(nФ) + i sin(nФ))
* In the problem
- The fifth root means z^(1/5)
- We can put 32 as a form a^n
∵ 32 = 2 × 2 × 2 × 2 × 2 = 2^5
∴ z = 2^5[cos(280°) + i sin(280°)]
* Lets find z^(1/5)
![*z^{\frac{1}{5}}=[2^{5}]^{\frac{1}{5} } (cos(\frac{1}{5})(280)+isin(\frac{1}{5})(280)](https://tex.z-dn.net/?f=%2Az%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%3D%5B2%5E%7B5%7D%5D%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D%20%28cos%28%5Cfrac%7B1%7D%7B5%7D%29%28280%29%2Bisin%28%5Cfrac%7B1%7D%7B5%7D%29%28280%29)
∴ z^(1/5) = 2[cos(56) + i sin(56)]
* The fifth root of 32[cos(280°) + i sin(280°)] is 2[cos(56°) + i sin(56°)]
Answer:
58.3% to the nearest tenth.
Step-by-step explanation:
The prime numbers from 1 to 6 are 2,3 and 5.
The probability of a prime number taken from the result of the 300 throws:
= (sum of the frequencies for 2, 3 and 5) / ( total throws)
= (60 + 55 + 60) / 300
= 0.5833 or 58.3%.
Answer:
y = 2/4x -2
Step-by-step explanation:
Answer =$388.75
25x.10= $2.50, 35x.15=$5.25, 350x.20=$70
$2.50+5.25+70=$77.75x5 days=$388.75
