Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
40mph for Car B I think. 45mph for Car A. 45(mph) times 4(h) is 180(distance) and 40 times 4.5 is also 180. Sorry if I'm wrong.
Answer: b. Y= -6/5x + 6/5
First find the slope of your two points, then write your equation in point-slope form. Using your equation in point-slope form, you can solve and convert it to slope-intercept form.
Answer:
the answer i got was 1159.1
Step-by-step explanation:
cos75 = 300/x
0.25881905 = 300/x
multiply everything by x
0.25881905x = 300
Divide everything by 0.25881905
x = 1159.1
is that close to any of your answers?
