How do you solve this problem?

Mathematics

2 answers:

Nesterboy [21]4 years ago

8 0

Girl this is mad hard idc

galben [10]4 years ago

7 0

M = (-5/4)n - 2

To solve for m, you need to isolate m on one side by performing the same function to both sides. So starting with:
-5n = 4m + 8

Subtract 8 from both sides
-5n - 8 = 4m

Divide both sides by 4
(-5/4)n - 2 = m

Swap sides
m = (-5/4)n - 2

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Solve for the x in the equation <img src="https://tex.z-dn.net/?f=x%20%2B%203x%20%2B%205x%20%2B%207x%20%2B%20...49x%20%3D%20

Flauer [41]

Answer:

x=1

Step-by-step explanation:

x+3x+5x+7x+...+49x=625

(1+3+5+7+...+49)x=625 (1)

now consider s= 1+3+5+7+...+49

a=1

d=3-1=2

l=49

l=a+(n-1)d

49=1+(n-1)2

49-1=(n-1)2

48/2=n-1

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n=24+1=25

s=n/2*(a+l)

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from (1)

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3 years ago

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Nataliya [291]

Answer:

(5,-5)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?

ZanzabumX [31]

Answer:

x = $\frac{12+\sqrt{138} }{6}$ and x = $\frac{12-\sqrt{138} }{6}$

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: $x=\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $x=\frac{-b-\sqrt{b^2-4ac} }{2a}$ .