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Charra [1.4K]
3 years ago
13

For what values of a is the value of the binomial 2a−1 smaller than the value of the binomial 7−1.2a?

Mathematics
2 answers:
Hunter-Best [27]3 years ago
8 0
To solve the problem shown bove you must apply the proccedure shown below:

 1. You have that:

 2a-1<<span>7−1.2a
 2a+1.2a<7+1
 3.2a<8
 a<8/3.2
 a<2.5

 2. Therefore, f</span><span>or what values of a is the value of the binomial 2a−1 smaller than the value of the binomial 7−1.2a?
</span><span>
 As you can see above, the answer for this question is:

 All the values of a between -</span>∞ and 2.5<span>
</span>
aleksandrvk [35]3 years ago
3 0

I actually got this answer from the other guy who answered here : Carlosego.

He had the right answer but thought about it too much and added some extra information that lead the answer off track. If you went back to what "a" is, you would get a<2.5.

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If sin A + sin^3 A = cos^2 A, prove that cos^6 A - 4cos^4 A + 8cos^2 A = 4.
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Answer:

Step-by-step explanation:

sinA(1+sin^2A) = cos^2A

sinA(2 -cos^2A) = cos^2A

Squaring both sides,

sin^2A(4-4cos^2A +cos^4A) = cos^4A

(1-cos^2A)(4-4cos^2A +cos^4A) = cos^4A

4-4cos^2A +cos^4A-4cos^2A+4cos^4A-cos^6A = cos^4A

4 -cos^6A +4cos^4A -8cos^2A = 0

cos^6A - 4 cos^4A + 8cos^2A = 4

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(6, -4)? is this on khan academy or smth

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Rational numbers are _____ natural numbers.
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Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region​
yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

<u>Concepts:</u>

Area of Square = s²

  • s = side

Area of Triangle = bh/2

  • b = base
  • h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

<u>Solve:</u>

Question # 16

<em>Step One: Find the total area of two squares</em>

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

<em>Step Two: Find the area of the blank triangle</em>

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

<em>Step Three: Subtract the area of the blank triangle from the total area</em>

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

<em>Step One: Find the length of PT</em>

Given:

  • PR = 4 cm
  • RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

<em>Step Two: Find the length of S to PT perpendicularly</em>

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Three: Find the area of ΔPST</em>

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Four: Find the length of Q to PT perpendicularly</em>

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

<em>Step Five: Find the area of ΔPQT</em>

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

<em>Step Six: Combine area of two triangles to find the total area</em>

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

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A Gardner wants to add 39 pounds of nutrient a and 16 pounds of nutrient b to her garden. Each bag of brand x provides 3 pounds
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Answer:

5 bags of brand x and 6 bags of brand y.

Step-by-step explanation:

Nutrient requirement for the garden:

39 pounds of nutrient a and

16 pounds of nutrient b

Component of each bag of brand x:

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Therefore, 5 bags of brand x will contain 15 pounds of nutrient a and 10 pounds of nutrient b

Component of each bag of brand y:

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Therefore, 6 bags of brand y will contain 24 pounds of nutrient a and 6 pounds of nutrient b

Altogether, she should buy 5 bags of brand x and 6 bags of brand y to meet the nutrient requirement of the garden

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