
a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =

=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34
Answer:
any idea about the length of the box
Answer:
x y
0 2
1 5
Step-by-step explanation:
Answer:
Ok
Step-by-step explanation:
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<h2><u>Solution</u>:-</h2>
• Surface area of a cylinder = 2πr(r + h) sq. units.
In the above diagram,
Radius (r) of the cylinder = 13 cm.
Height (h) of the cylinder = 39 cm.
<h3>• Taking value of π = 3.14</h3>
Hence, Surface area of the cylinder = 2 × 3.14 × 13(13 + 39)
Surface area of the cylinder = (81.64 × 52) cm²
Surface area of the cylinder = 4245.28 cm²
The surface area of the cylinder is <u>4</u><u>2</u><u>4</u><u>5</u><u>.</u><u>2</u><u>8</u><u> </u><u>cm²</u>. [Answer]