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3 years ago

2 triangles are shown. The first triangle has side lengths 35, 20, and 20. The second triangle has side lengths x, 44, 44.

Mathematics

2 answers:

slavikrds [6]3 years ago

5 0

Answer:

$x = 77$

Step-by-step explanation:

Given

$First \to Second$

$35 \to x$

$20 \to 44$

Required

Find x by SSS

Represent the triangle sides as a ratio

$35 : x = 20 : 44$

Express as fraction

$\frac{x}{35} = \frac{44}{20}$

Multiply by 35

$x = \frac{44}{20} * 35$

$x = \frac{44 * 35}{20}$

$x = \frac{1540}{20}$

$x = 77$

timama [110]3 years ago

5 0

Answer:

ccccccccccccccccccccccccccc

Step-by-step explanation:

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3 years ago

Harry buys a wand for $12.50 plus 8% tax. Ron buys his sister a diary for $13 plus 8% tax. Write the sum, in dollars, that Harry

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Answer:

$27.54

Step-by-step explanation:

The straightforward way to do this is to compute the tax and total on each amount, then add those together. There is an easier way.

($12.50 + 0.08·12.50) + ($13.00 + 0.08·13.00) = $12.50·1.08 +13.00·1.08

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2 years ago

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RoseWind [281]

Answer:

Step-by-step explanation:

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3 years ago

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Vitek1552 [10]

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3 years ago

A human gene carries a certain disease from the mother to the child with a probability rate of 34%. That is, there is a 34% chan

eimsori [14]

Answer:

The probability that at least one of the children get the disease from their mother is P=0.7125.

Step-by-step explanation:

This can be modeled as a binomial random variable.

The parameter p=0.34 is the probability of a child being infected, and is constant and independent of the other events.

The parameter n=3 is the number of children (sample size).

Then, we have to calculate the probabilty that at least one of the children get the disease from their mother. That is:

$P(x\geq1)$

The probability of exactly k children being infected can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}$

Then, the easiest way to calculate this probability is using the complement: the value of the probability is 1 (or 100%) less the probability that no children gets infected.

$P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{3}{0} p^{0}(1-p)^{3}=1*1*0.2875=0.2875\\\\\\P(x\geq1)=1-0.2875=0.7125$

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3 years ago