If you were working with a flat rectangle and you were given the diagonal,
you'd want to use the Pythagorean theorem to choose two sides whose
squares would add up to the square of the diagonal.
It works exactly the same with a 3-D box. We need three dimensions for
the box, whose squares add up to the square of the diagonal between
opposite corners. That's (4)² = 16.
So (L)² + (W²) + (H²) = 16 . From there, you're completely free to pick any
numbers you want, just as long as their squares add up to 16. There are
an infinite number of possibilities. Here are a few:
1 x 1 x √14
1 x 2 x √11
2 x 2 x √8
2 x 3 x √3
1 x 3 x √6
9514 1404 393
Answer:
2. 15 cents/min
3. 7/4 gallon/week = 1.75 gal/wk
Step-by-step explanation:
You want to convert the units without changing the rate. You do this by making use of conversion factors. Each conversion factor has a value of 1, but changes the units. (It has a value of 1 because the quantity in the numerator is equal to the quantity in the denominator.)
In general, you know that when the numerator and denominator of a fraction are the same thing, they cancel, leaving a value of 1. When a variable (or unit) is involved, the cancelled variables (or units) simply disappear.
For example, multiplying (9 dollars)×(100 cents)/(1 dollar) gives ...
The units of "dollar" cancel, leaving cents. Note that we did this by choosing a conversion factor with units we want in the place we want, and units we don't want on the other side of the fraction bar.
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2) We want cents in the numerator, so our conversion factor will be (100 cents)/(1 dollar). And we want minutes in the denominator, so our other conversion factor will be (1 hour)/(60 minutes). Multiplying by these conversion factors, our rate becomes ...
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3) We want gallons in the numerator, so that conversion will be done by (1 gal)/(8 pt). We want weeks in the denominator, so the conversion for that is (7 day)/(1 week).
Answer:
y = 300
Step-by-step explanation:
y = 250 (1+0.2)
First add the 1 and 0.2
y=250(1.2)
multiply 250 with 1.2
y = 300
:)
We can write this as the difference of squares:
(5b⁸+8c)(5b⁸-8c)
To write as the difference of squares, take the square root of each term first:
√25b¹⁶ = 5b⁸; √64c² = 8c
Now we write this as a sum in one binomial and a difference in the other:
(5b⁸+8c)(5b⁸-8c)