Answer:
Puedes mandarma la foto
Step-by-step explanation:
Porfa
-x + 2y = 4
2y = x + 4
y = 1/2x + 2.....slope here is 1/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So the slope we need is -2 (see how I flipped the slope and changed the sign)
y = mx + b
slope(m) = -2
(-2,1)...x = -2 and y = 1
now we sub and solve for b, the y int
1 = -2(-2) + b
1 = 4 + b
1 - 4 = b
-3 = b
so ur perpendicular line is : y = -2x - 3
Answer:
Co me he re tjyvynoqtu guys
Answer:
See explanation
Step-by-step explanation:
Consider two triangles ABF and EDF. These triangles are two right triangles, because angles B and D are right anges.
In these triangles,
- ∠ABF ≅ ∠EDF - as two right angles;
- BF ≅ FE - given;
- ∠AFB ≅ ∠EFD - as vertical angles when two lines AD and BE itersect.
By ASA postulate (or HA postulate) these triangles are congruent, so
ΔABF ≅ ΔEDF
Congruent triangles have congruent corresponding parts, so
FA ≅ EF
The correct answer is C. if you plug zero in for 'x' you will get the y-intercept.
-2(0-2)(0-4)= -2(-2)(-4)=-16
Next set each factor equal to zero to get the x-intercepts.
(x-2)=0 x = 2 (2,0)
(x-4) = 0 x = 4 (4,0)
I hope this helps
