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kipiarov [429]
3 years ago
6

DETAILS

Mathematics
1 answer:
Nina [5.8K]3 years ago
4 0

The perimeter of the rectangle as a function of w only is P(w) = 2[√(324 - w²) + w]

The perimeter of the rectangle P = 2(h + w)

Since the diagonal is D = 18 feet, using Pythagoras' theorem, we have that

D² = h² + w²

So, making h subject of the formula, we have

h = √(D² - w²)

h = √(18² - w²)

h = √(324 - w²)

Since the perimeter of the rectangle P = 2(h + w), substituting the value of h into P, we have

P = 2(h + w)

P = 2[√(324 - w²) + w]

P(w) = 2[√(324 - w²) + w]

So, the perimeter of the rectangle as a function of w only is P(w) = 2[√(324 - w²) + w]

The angle θ as a function of w only is θ(w) = sin⁻¹[w/18]

Using trigonometric functions, sinθ = w/D

since D = 18, substituting the value of D into the equation, we have

sinθ = w/18

Taking inverse tan of both sides, we have

θ = sin⁻¹[w/18]

θ(w) = sin⁻¹[w/18]

So, the angle θ as a function of w only is θ(w) = sin⁻¹[w/18]

Learn more about perimeter of a rectangle here:

brainly.com/question/7538991

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Answer:

B) -2x+2y=-2

Step-by-step explanation:

we have

x+y=11 ----> equation A

2x-3y=-3 ----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both graphs

using a graphing tool

The solution is the point (6,5)

see the attached figure

Remember that

If a equation is added to the system so that the solution does not change, then the solution of the system must be a solution of the equation added

<u><em>Verify each case</em></u>

The solution of the system is (6,5)

substitute the value of x and the value of y in each equation

case A) x-y=2

6-5=2

1=2 ----> is not true

therefore

This equation can't be added to the system

case B) -2x+2y=-2

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-12+10=-2

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therefore

This equation can be added to the system

case C) 3x+y=20

3(6)+5=20

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23=20 ----> is not true

therefore

This equation can't be added to the system

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This equation can't be added to the system

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But in expressing her own take on both issues, be it attending church as a show of one's religiousness, or death, Dickinson asserts her own beliefs and opinions against the 'normal'. And in both poems, she is forthright and confident in what she believes and shows.

Thus, the correct answer is option C.

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