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melisa1 [442]
4 years ago
6

Discuss a main factor negatively affecting species around the world and what scientist are doing in order to combat those proble

ms.
Physics
1 answer:
stiks02 [169]4 years ago
3 0
These are the common main factors negatively affecting species around the world:

• Invasive species. The overview of non-native species into an ecosystem can intimidate endemic wildlife, distress human health and upset economies. Scientist solution contain making systems to avoid introduction of invasive species in the first place effectively monitoring for new infestations and fast abolition anew noticed intruders. 

• Over-exploitation. Overhunting, overfishing and overharvesting give importantly to the damage of biodiversity which is killing of numerous species over the past several hundred years. The solution is conservation and constant consciousness neighboring over-exploitation mostly poaching and overfishing. 

• Climate change. Alterations in climate over our planet past have altered life on earth in the long run which ecosystems have originate and left and species regularly go nonexistent. The solution must be reducing carbon prints and promoting education.

• Deforestation and habitat loss. This is a direct cause of extinction and loss of biodiversity. The solution is recommending stronger scientific forest protection laws. 

• Lastly is the pollution. Acid rain which is normally initiated by the burning of fossil fuels can acidify smaller bodies of water and soil harmfully affecting the species that live there by altering breeding and nourishing habits. The solution must combat atmospheric and hydrologic pollution. 
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A 185 g block is pressed against a spring of force constant 1.60 kN/m until the block compresses the spring 10.0 cm. The spring
denis-greek [22]

Answer:

d = 5.10 m

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As we know that here on the plane of the inclined there is no frictional force

So in these cases we can say that total mechanical energy will always remains conserved

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spring potential energy = gravitational potential energy of the block

as we know from the formula

\frac{1}{2}kx^2 = mgh

now plug in the values in it

\frac{1}{2}(1.60 \times 10^3)(0.10)^2 = (0.185)(9.81)h

8 = 1.81 h

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now as we know that the angle of inclination is 60 degree and height raised is 4.42 m

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