Answer:
(a) 62.5 m
(b) 7.14 s
Explanation:
initial speed, u = 35 m/s
g = 9.8 m/s^2
(a) Let the rocket raises upto height h and at maximum height the speed is zero.
Use third equation of motion


h = 62.5 m
Thus, the rocket goes upto a height of 62.5 m.
(b) Let the rocket takes time t to reach to maximum height.
By use of first equation of motion
v = u + at
0 = 35 - 9.8 t
t = 3.57 s
The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.
The study of the moon as well as the stars is astronomy
Answer:
Explanation:
Using Pascal laws, which states that pressure are the input equals the pressure at the output.
Pressure is given as force/area
P1=P2
Then,
F1/A1=F2/A2
Cross multiply
F1A2=F2A1
Given that
Ae=0.5m² area of effort
Al=5m² area of load
Fl=? Force if load
Fe= 100N. Force of effort
Then applying pascal
Fl/Al=Fe/Ae
Fl/5=100/0.5
FL/5=200
Fl=200×5
Fl=1000N
The first safety load is 1000N
Answer:
self-maintained discharge
Explanation: