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Alexus [3.1K]
3 years ago
5

For an object of mass m with a force F, which equation can be used to

Physics
1 answer:
jasenka [17]3 years ago
5 0
Force = mass x acceleration
so to find acceleration you would do force divided by mass
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A 9-inch tall sunflower is planted in a garden and the height of the sunflower increases exponentially. 5 days after being plant
stira [4]

Answer:

a)  h / h₀ = 1,682

, b) h / h₀ = 1.11

, c)    h / h₀ = 2.07

Explanation:

For this exercise let's look for the growth equation, as they indicate that it is exponential

        h = h₀ e^{\alpha t}

The initial height is 9 ”, so the constant

         h₀ = 9”

Let's use the given values

       h = 15.1655”

       t = 5 days

       h / h₀ = e^{\alpha t}

      α = 1 / t ln h / h₀

       α = 1/5 ln (15.1655 / 9)

      α = 0.104

       h = 9 e^{0.104 t}

a) the growth factor is the relationship between the initial value and the current value

        h / h₀ = e^{0.104  5}

        h / h₀ = 1,682

b) for t = 1 day

       h / h₀ = e^{0.104 1}

       h / h₀ = 1.11

c) for t = 7 days

       h / h₀ = e^{0.104 7}

       h / h₀ = 2.07

8 0
3 years ago
A straight 1.20 m long conductor has a 2.00 A current travelling toward the East. Earth's magnetic field in this location is 4.9
KATRIN_1 [288]

Answer:

Force's magnitude=1.176\,10^{-4}\,N

Direction: down (towards the center of the Earth)

Explanation:

Recall that the magnetic force on a conductor of length L carrying a current I in a magnetic field B is given by the equation: F=I\,L\,B in the case the magnetic field B and the direction of the current are at 90 degrees from each other (which is our case). The direction of the force will be given by the "right hand rule" associated with the vector product that defines this force.

Since the current is moving East, and the magnetic field of the Earth goes from North to South, the resultant Force vector will be pointing towards the Earth (and perpendicular to the plane defined by the current's direction and the magnetic field B)

The magnitude of the force, is given by the formula above, and given that all quantities to be considered are is SI units, it will result in Newtons (N):

F=I\,L\,B\\F=2\,*\,1.2\,*\,4.9\,10^{-5}\,N\\F=1.176\,10^{-4}\,N

8 0
4 years ago
I need working steps and answers
DIA [1.3K]

Explanation:

I will definitely explain you if you follow me please

6 0
2 years ago
WILL GIVE BRAINLESS IF U ANSER ALL CORECTLY
erma4kov [3.2K]

Answer:

1-As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

2-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

3-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks.

4-Rain shadow deserts are formed because tall mountain ranges prevent moisture-rich clouds from reaching areas on the lee, or protected side, of the range.

5-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

6-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

Explanation:

#6 and 5 are the same

5 0
3 years ago
(Double points) A mechanic used a wrench 0.6 meters long to loosen rusted lug nuts on a truck wheel. By standing on the end of t
Korolek [52]

Answer:

Torque, \tau=588\ N-m

Explanation:

It is given that,

Length of the wrench, l = 0.6 m

Mass of the wrench, m = 100 kg

We know that the torque applied by mechanic is given by :

\tau=Fl

\tau=mgl

\tau=100\times 9.8\times 0.6

\tau=588\ N-m

So, the torque applied by the mechanic is 588 N-m. Hence, this is the required solution.

3 0
3 years ago
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