Answer: If I’m not mistaken, the largest area is 75 m2 and the smallest is 2 m2
Step-by-step explanation:
For both : since they are asking for the area, you should calculate the perimeter.
So for the largest area, since you know that you have 40 fences, and each are 1 meter long, and they’re also asking for the largest rectangular area, this means that only the opposite sides will have the same length, so in order to divide the rectangle with the 40 one-meter fences, the biggest sides have to be 15 meters long (so for both : 15x2=30 meters). Then you deduct from 40, 30 : 40-30 = 10 which then you can devide by 2 and find 5 + 5 and that means that the 2 smallest sides will be 5 meters long each. Then finally to calculate the perimeter you should do the biggest side multiplied by the smallest side : 15 x 5 and you find 75 m2 (squaremeters), if I’m not mistaken.
And for the smallest area you take the smallest possibilities knowing that only the opposite sides should have the same length and not all of them, so you do 1 x 2 and you find 2 m2.
Answer:
D is not a supported statement
Step-by-step explanation:
Let take them one by one:
A: from table: 0.57; in statement: 0.5
0.57 > 0.5 so this is supported
B: from table: 0.2+0.16=0.36; in statement: 1/3=0.33,
0.36>0.33 so this is supported
C: 0.07 is the least, so this is supported
D: the table DOES NOT show number of students, but proportions. So statement '7 students' IS NOT supported
E: from table 0.20 overslept. 0.2 < 1/4=0.25, so this is supported
Answer: Maybe it's the third one I'm not completely sure. don't take my word for it.
Step-by-step explanation:
Answer:
0.61
Step-by-step explanation:
Pr (female) = total number of females(n')/Total number of students(n)
Where P(female) = probability of selectinga female
Pr(female) = n'/n................. Equation 1
Given: n = 44 students, n' = 15+12 = 27 females
Substitute into equation 1
Pr(female) = 27/44
Pr(female) = 0.61.
Hence the probability of selecting a female is 0.61
