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Varvara68 [4.7K]
3 years ago
11

Is the expression below completely factored? If not, complete the factorization.

Mathematics
1 answer:
Ket [755]3 years ago
6 0

Answer:

A) No, because the greatest common factor is 8y?, and the completely factored form is 8y2(4y2 - 6y + 3).

Step-by-step explanation:

Considering the expression

4y(8y3 – 12y2 + 6y)

From the elements in the parenthesis, 2 and y can still be factored out such that what will be left of each element

8y3/2y = 4y2

12y2/2y = 6y

6y/2y = 3

Hence

4y(8y3 – 12y2 + 6y) = 4y*2y(4y2 - 6y +3)

= 8y2(4y2 - 6y + 3)

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3 years ago
Which of the following can be a Pythagorean triplets?:
PolarNik [594]

<h2>Answer :-</h2>

As we know that,

Pythagoras triplet

1) a² + b² = c²

Let

\sf \: {2}^{2} + {2}^{2} = {4}^{2}

\sf \: 4 + 4 = 16

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<h3>Hence, A can't be Pythagoras triplet</h3>

2) a² + b² = c²

\sf \:5 {}^{2} + {12}^{2} = {13}^{2}

\sf \: 25 + 144 = 169

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<h3>Therefore, B can be Pythagoras triplet</h3>

3)a² + b² = c²

\sf {3}^{2} + {5}^{2} = {6}^{2}

\sf 9 + 25 = 36

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<h3>Hence, C can't be Pythagoras triplet</h3>

4) a² + b² = c²

\sf {5}^{2} + {4}^{2} = {7}^{2}

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<h3>Hence, D can't be Pythagoras triplet</h3>

<h2 /><h2>Therefore :-</h2>

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3 years ago
Can you guys please help me with this. It is graded. Thanks.
telo118 [61]
The answer is C, $8.15
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