First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
Answer:
6:15:11
Step-by-step explanation:
We first start off with 24:60:44. We then know that the greatest common factor is 4, so we divide the ratio by 4 to get 6:15:11.
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(-4/5) / 3 =
-4/5 * 1/3 =
-4/15 mile per minute
Answer:
Randall: 44, Amy: 35
Step-by-step explanation:
Four years ago, their age added up to 71. Since four years have passed and they've each grown four years older since then, their ages added up together is 79. Here is the equation for Amy: x + (x + 9) = 79. We can simplify to get 35. Now we add 9 to 35 to get Randall's age. So, Amy's age is 35 and Randall's age is 44, and 35 + 44 = 79.
Answer:
B. 2.75 mph
Step-by-step explanation:
If it took him 2 hours to walk 5.5 miles, 5.5 ÷ 2 = 2.75, which is what he walked in a single hour, meaning he was walking 2.75 mph