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expeople1 [14]
3 years ago
5

What is the radius of a circle with an area of 78.5 cubic inches? Use 3.14 for pi. Enter your answer in the box.

Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

Answer:

5 inches

Step-by-step explanation:

Given : A circle with an area of 78.5 cubic inches .

To Find: What is the radius of a circle with an area of 78.5 cubic inches?

Solution :

Formula of area of circle:

\pi r^{2}

where r is the Radius of circle

Since we are given thet the area of circle 78.5 cubic inches

Using the above formula :

78.5=\pi r^{2}

Using π =3.14

78.5=3.14*r^{2}

\frac{78.5}{3.14} =r^{2}

25=r^{2}

\sqrt{25} =r

r=5

Thus , 5 inches is the radius of a circle with an area of 78.5 cubic inches

UkoKoshka [18]3 years ago
5 0

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=78.5 \end{cases}\implies 78.5=\pi r^2\implies \cfrac{78.5}{\pi }=r^2 \\\\\\ \sqrt{\cfrac{78.5}{\pi }}=r\implies 4.9987\approx r

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Use finite approximation to estimate the area under the graph of f(x) = 5^2 and above the graph of f(x) = 0 from X(o) = 0 to x(n
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Finite approximation method of estimating the area under the curve of the

given function makes use of rectangular approximation of the area.

The correct responses are;

i) The estimated area using a lower sum with two rectangles of equal width is <u>1,715 square units</u>.

ii) The estimated area using a lower sum with four rectangles of equal width is <u>3,001.25 square units</u>.

iii) The estimated area using an upper sum with two rectangles of equal width is<u> 8,575 square units</u>.

iv) The estimated area using a upper sum with four rectangles of equal width is <u>6,431.25 square units</u>.

Reasons:

The given function is f(x) = 5·x²

The given domain is x₀ to x₁₄

i) Estimate using lower sum with two rectangles of equal width;

Let \ \Delta x = \dfrac{14}{2} = 7 \ we \ get;

f(0) = 0

f(7) = 5 × 7² = 245

A = 0 × 7 + 245 × 7 = 1,715

The estimated area using a lower sum with two rectangles of equal width

is <u>1,715 square units</u>.

ii) Estimate using lower sum with four rectangles of equal width;

Let \ \Delta x = \dfrac{14}{4} = 3.5 \ we \ get;

f(0) = 0

f(3.5) = 5 × 3.5² = 61.25

f(7) = 5 × 7² = 245

f(10.5) = 5 × 10.5² = 551.25

A = 0 × 3.5 + 61.25 × 3.5 + 245 × 3.5 + 551.25 × 3.5 = 3,001.25

The estimated area using a lower sum with four rectangles of equal width is <u>3,001.25 square units</u>.

iii) Estimate using an upper sum with two rectangles of equal width;

Let \ \Delta x = \dfrac{14}{2} = 7 \ we \ get;

f(7) = 5 × 7² = 245

f(14) = 5 × 14² = 980

A = 245 × 7 + 980 × 7 = 8575

The estimated area using an upper sum with two rectangles of equal width

is <u>8,575 square units</u>.

iv) Estimate using an upper sum with four rectangles of equal width;

Let \ \Delta x = \dfrac{14}{4} = 3.5 \ we \ get;

f(3.5) = 5 × 3.5² = 61.25

f(7) = 5 × 7² = 245

f(10.5) = 5 × 10.5² = 551.25

f(14) = 5 × 14² = 980

A = 61.25 × 3.5 + 245 × 3.5 + 551.25 × 3.5 + 980 × 3.5 = 6,431.25

The estimated area using a upper sum with four rectangles of equal width

is <u>6,431.25 square units</u>.

Learn more here:

brainly.com/question/2264277

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