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lana [24]
3 years ago
14

The value of z varies inversely with the value of w. The constant of variation is 2. Which are possible values for z

Mathematics
1 answer:
serious [3.7K]3 years ago
7 0

Answer: A C D

Step-by-step explanation:

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Yuri purchased 8 trees to have planted at his house. The store charged a delivery fee of $5 per tree.
kari74 [83]

Answer:

The answer would be 16, because the delivery of the 8 trees costed 40, and the overall cost was 168, so you would subtract 40 for the delivery, and divide 128 by 8.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which description compares the vertical asymptotes of function A and function B correctly?
neonofarm [45]

Answer:

Option B:

Function A has a vertical asymptote at x = 1

Function B has a vertical asymptote at x = -3

Step-by-step explanation:

A function f(x) has a vertical asymptote if:

\lim_{x \to\\k^+}f(x) = \±\infty\\\\ \lim_{x \to\\k^-}f(x) = \±\infty

This means that if there is a value k for which f(x) has infinity or a -infinity then x = k is a vertical asymptote of f(x). Therefore, the closer x to k approaches, the closer the function becomes to infinity.

We can calculate the asymptote for function A.

\lim_{x \to \\1^+}(\frac{1}{x-1})\\\\ \lim_{x \to \\1^+}(\frac{1}{1^-1})\\\\ \lim_{x \to \\1^+}(\frac{1}{0}) = \infty\\\\and\\ \lim_{x \to \\1^-}(\frac{1}{x-1})\\\\\lim_{x \to \\1^-}(\frac{1}{0}) = -\infty

Then, function A has a vertical asymptote at x = 1.

The asymptote of function B can be easily observed in the graph. Note that the function b is not defined for x = -3 and when x is closest to -3, f(x) approaches infinity.

Therefore x = -3 is asintota of function B.

Therefore the correct answer is option B.

8 0
3 years ago
Is 11.22 rational???
kobusy [5.1K]

Answer:

Yes

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Multiply.
goblinko [34]

Answer:

the answer for 323.34  is 10,982

Step-by-step explanation:

I tried very hard to answer this question.

you have to multiply 323.34  to get  10,982.

hope this hlep you.

8 0
3 years ago
Assume that the function call operator() is overloaded for data type String in the usual sense of selecting a substring from a l
krek1111 [17]

Answer:

"EF"

Step-by-step explanation:

Given

String1 = "ABCDEFGHI"

Substring : String1(4,2)

To solve this, one must understand the following

1. The function call operator () is used to overload objects of class type.

2. A copy constructor must receive its argument by reference to prevent an otherwise infinite recursion.

3. overload ( ), doesn't mean that one is not creating a new way to call a function; instead, it is a way to create an operator function that can be passed an arbitrary number of parameters

Having pointed out this,

The string to overload goes thus

String1 = "ABCDEFGHI"

The parameters goes thus

String1(4,2)

To represent this properly, we have

("ABCDEFGHI",4,2)

Which means to return 2 strings starting from the 4th index character.

It should be noted that index starts at 0.

So, the character at the 4th index is "E"

Then, we count 2 characters starting from E (i.e. E, inclusive)

This gives

"EF"

So, the returned string is "EF"

6 0
3 years ago
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