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Fudgin [204]
3 years ago
14

Please help and show your work . Thanks if the picture is upside down turn your device on portrait by locking it so it won't tur

n

Mathematics
1 answer:
Bezzdna [24]3 years ago
3 0
So we know that the bag has total 15 cookies, and 1 cookie that does not have any raisin. Finally, the probability that one cookie won't have any raisin is 1/15 or 7 percent. Hope it help!
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Solve for x<br><br> It is geometry so anyone got it?
Sauron [17]

Answer:

X=26

Step-by-step explanation:

180-105=75

26•2=52. 52+23=75°

7 0
3 years ago
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Round 10.054 To 2 decimal places
antoniya [11.8K]
The answer to "Round 10.054 To 2 decimal places" is 10.05
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3 years ago
A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded
Crank

Answer:

A=81(\pi-1)\ in^2

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

A=\pi r^{2}

we have

r=18/2=9\ in ---> the radius is half the diameter

substitute

A=\pi (9)^{2}\\A=81\pi\ in^2

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

D^2=2b^2

where

b is the length side of the square

we have

D=18\ in

substitute

18^2=2b^2

solve for b^2

b^2=162\ in^2 -----> is the area of the square

Divide by 2

162/2=81\ in^2

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The  area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

A=(81\pi-81)\ in^2

simplify

A=81(\pi-1)\ in^2

8 0
3 years ago
The cost of 6 CDs are $12, $13, $20, $20, $12.50 and $18.50. What is the range?
ra1l [238]
I think $8. That’s the difference between the highest and lowest number.
4 0
2 years ago
What is 42 divided 7\8
Setler [38]
48 I think hope this helps
6 0
3 years ago
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