Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4

Subtracting Eqn 1 from Eqn 3

Dividing both sides by 8

Putting x=1.5 in Eqn 1

Dividing both sides by 8

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
Learn more about elimination method at:
#LearnwithBrainly
Answer:
D
Step-by-step explanation:
We will use the 2 coordinates marked on the graph as the reference.
The coordinates are:
A(4,-2)
B(0,3)
We know that the standard form for equation of line is:
y = mx+c
where m is the slope of the equation
and c is the y-intercept.
Very clearly, the y-intercept is where the line intercepts the y line.
and in this case, y-intercept = c = 3.
Now we know that the equation of line is now
y = mx + 3
To find m, the slope, we can use the 2 above coordinates.
slope of line = 
(Note: There is a 2nd way to find the slope in this case, let me know if you are interested to find out.)
Equation of line: 
Therefore the answer is D.
Answer:
a) 
b) 
Step-by-step explanation:
a) 
1. Distribute the second power (2) outside the first pair of parenthesis:

= 
2. Distribute the third power (3) outside the second pair of parenthesis:

= 
3. Combine like terms:

--------------------------------------------
b) 
1. Factor the number 6 (= 2 · 3):

2. Cancel the common factor (2):

3. Cancel out
in the numerator an denominator:

hope this helps!
It equals 23 degrees Fahrenheit. So -5c=23f
1) surface area = 18m^2 * pi * 26m = <span>8424pi m^2</span>