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70 ft per sec going upward 3 sec from 6 ft high should reach 216 ft, but unfortunately gravity is pulling it and at some point it starts to go backward (at 2.176 second), so to compensate the upward slowing down and distance dropped, use -32.176 times 3 square times 1/2 = -144.792 which is the natural drop distance if the football is released mid air without a initial speed after 3 seconds. 216 - 144.792 = 71.208 ft high.
Answer:
none of them
Step-by-step explanation:
The area (A) of a triangle is calculated as
A = 0.5 × base × perpendicular height
Here the base is BC and perpendicular height is AD, hence
Area of ΔABC = 0.5 × BC × AD
Answer:
the answer is 6.45
Step-by-step explanation: