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3 years ago

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There are 85 sixth grade students in Ms. eelings class. This makes up 34% of the students in 6th grade in the school. What are t

he titak amount of students in 6th grade.
(please show proportions)

1 answer:

Fed [463]3 years ago

5 0

Answer:

There are <u>250 students</u> in the 6th grade.

Step-by-step explanation:

[] Let us do "number of students" over the percentage. We will use x as the total number of students in the 6th grade.

-> 35% and 100% can be divided by 100 to become decimals

Set up a proportion:

$\frac{85}{0.34} =\frac{x}{1}$

Cross multiply:

85 = 0.34x

Divide both sides by 0.34:

250 = x

Reflexive property:

x = 250

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

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Solve for L. m=LN+2/K

Iteru [2.4K]

Answer:

$l = \frac{m - \frac{2}{k} }{n} \\ \\$

Step-by-step explanation:

$m = ln + \frac{2}{k} \\ m - \frac{2}{k} = ln \\ \frac{m - \frac{2}{k} }{n} = \frac{ln}{n} \\ l = \frac{m - \frac{2}{k} }{n} \\$

hope this helps

brainliest appreciated

good luck! have a nice day!

6 0

4 years ago

Match the parabolas represented by the equations with their foci.

Elenna [48]

Function 1 $f(x)=- x^{2} +4x+8$

First step: Finding when $f(x)$ is minimum/maximum
The function has a negative value $x^{2}$ hence the $f(x)$ has a maximum value which happens when $x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2$ . The foci of this parabola lies on $x=2$ .

Second step: Find the value of y-coordinate by substituting $x=2$ into $f(x)$ which give $y=- (2)^{2} +4(2)+8=12$

Third step: Find the distance of the foci from the y-coordinate
$y=- x^{2} +4x+8$ - Multiply all term by -1 to get a positive $x^{2}$
$-y= x^{2} -4x-8$ - then manipulate the constant of y to get a multiply of 4
$4(- \frac{1}{4})y= x^{2} -4x-8$
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is $12- \frac{1}{4}=11.75$

Hence the coordinate of the foci is (2, 11.75)

Function 2: $f(x)= 2x^{2}+16x+18$

The function has a positive $x^{2}$ so it has a minimum

First step - $x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4$
Second step - $y=2(-4)^{2}+16(-4)+18=-14$
Third step - Manipulating $f(x)$ to leave $x^{2}$ with constant of 1
$y=2 x^{2} +16x+18$ - Divide all terms by 2
$\frac{1}{2}y= x^{2} +8x+9$ - Manipulate the constant of y to get a multiply of 4
$4( \frac{1}{8}y= x^{2} +8x+9$

So the distance of focus from y-coordinate is $\frac{1}{8}$ to the north of $y=-14$
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: $f(x)=-2 x^{2} +5x+14$

First step: the function's maximum value happens when $x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25$
Second step: $y=-2(1.25)^{2}+5(1.25)+14=17.125$
Third step: Manipulating $f(x)$
$y=-2 x^{2} +5x+14$ - Divide all terms by -2
$-2y= x^{2} -2.5x-7$ - Manipulate coefficient of y to get a multiply of 4
$4(- \frac{1}{8})y= x^{2} -2.5x-7$
So the distance of the foci from the y-coordinate is - $\frac{1}{8}$ south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when $x=8.5$ and $y=79.25$ . The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when $x=-2.75$ and $y=-10.125$ . Manipulating coefficient of y, the distance of foci from y-coordinate is $\frac{1}{8}$ to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when $x=1.5$ and $y=9.5$ . The distance of the foci from the y-coordinate is $\frac{1}{8}$ to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

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3 years ago

HELP ME PLEASE SOMEONE!!

KiRa [710]

You have the correct answer being (-5,3). Simply add the parentheses around the point

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2 years ago

Answer for when sam goes to a restaurant, he always tips the server $2 plus 10% of the cost of the meal. if sam's distribution o

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Given that S<span>am's distribution of meal costs has a mean of $9 and a standard deviation of $3, this means that the range of Sam's meal cost that are within one standard deviation is given by ($9 - 3, $9 + 3) = ($6, $12).

Given that Sam </span><span>always tips the server $2 plus 10% of the cost of the meal, this means that when the cost of the meal is $9, Sam tips $2 + (0.1 x 9) = $2 + $0.9 = $2.90

Therefore, the mean of the distribution of Sam's tips is $2.90

Similarly, the </span><span>range of Sam's tips that are within one standard deviation is given by ($2 + 0.1(6), $2 + 0.1(12)) = ($2 + 0.6, $2 + 1.2) = ($2.6, 3.2) = ($2.9 - $0.3, $2.9 + $0.3)

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3 years ago

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Answer:

Hello! Answer: B

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3 years ago

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