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never [62]
3 years ago
10

What is the value of 80-5(x^2-y)+y when x=4 and y=6

Mathematics
1 answer:
egoroff_w [7]3 years ago
8 0

Answer:h

Step-by-step explanation:

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ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th
Misha Larkins [42]

Answer:

a.P(E_1/A)=0.0789

b.P(E_2/A)=0.395\

c.P(E_3/A)=0.526

Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

P(A/E_2=0.03

P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

7 0
4 years ago
-34 + 91 = -3 (4x + 1) + 6x
ra1l [238]

-34 + 91 = -3(4x+1) + 6x\\57 = -12x - 3 + 6x\\6x = -60\\x= -10\\

Thus x = -10.

Hope that helps!

3 0
3 years ago
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In ANOP, the measure of P=90°, PN = 95 feet, and OP = 31 feet. Find the measure
sweet-ann [11.9K]

Answer: 72

Step-by-step explanation:

6 0
3 years ago
If 3+4+8=15 then 8+3+4=15 right?
Vlada [557]
Yes same thing

love ya
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Frankie❤
4 0
3 years ago
If the pattern continues, how many stars will be in the Stage 15 figure?
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There would be 45 stars in a stage 15 patteren

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