What is the value of 80-5(x^2-y)+y when x=4 and y=6
1 answer:
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Answer:
x = -3
Step-by-step explanation:
The line parallel to x=8 is another vertical line:
x = constant
To make it go through a point with an x-coordinate of -3, the constant must be -3.
Your line is ...
x = -3
