1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eduardwww [97]
3 years ago
10

The figure shown has a parallelogram on top and a rectangle below it:

Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Area of a parallelogram = b×h
= 13.4×48.2
= 645.88 inches square
Area of rectangle = l×b
=7.3×48.2
= 351.86
Area of the figure = (b×h) + (l×b)
=645.88+351.86
= 997.74 inches square
Therefore, the answer is option C

You might be interested in
Find the product 8/6n - 4(9n^2 -4)
Brrunno [24]

Answer:

- (27n^3 - 12n - 1) over 3n

Step-by-step explanation:

4 0
3 years ago
Can u guys PLEASE answer this question ASAP. THIS IS EXTREMELY URGENT
skelet666 [1.2K]

Answer:

14.55 hope this help

Step-by-step explanation:

3 0
3 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2
Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either   \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t  = e^−2(0)  = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt}  = -2te^{-2t}  = -2(0)e^{-2(0)}  = 0

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0
3 years ago
in question 9-12,determine if the equation of the line is in point-slope form or slope-intercept form and determine the slope of
rusak2 [61]
9 and 12 are slope-intercept form and 10 and 11 are point-slope form
4 0
3 years ago
A 14​-foot ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground 9 fee
timama [110]

Answer:

10.7 feet

Step-by-step explanation:

The ladder, the ground and the wall form the shape of a right angled triangle as shown in the image below.

The hypotenuse of the triangle is 14 feet (length of ladder)

The base of the triangle is 9 feet long (the distance from the base of the ladder to the wall)

We need to find the height of the triangle. We can apply Pythagoras rule:

hyp^2 = a^2 + b^2

where hyp = hypotenuse

a = base of the triangle

b = height of the triangle

Therefore:

14^2 = 9^2 + b^2\\\\196 = 81 + b^2\\\\b^2 = 196 - 81 = 115\\\\b = \sqrt{115} \\\\b = 10.7 feet

The wall reaches 10.7 feet high.

3 0
4 years ago
Other questions:
  • What is the answer to these question<br> 1:1/3y-1/2=5<br> 2:5n+1/2=1/6
    7·1 answer
  • (PLEASE HELP I WILL MARK YOU BRAINLIEST)what’s the standard form of 2.33x10^-8
    13·2 answers
  • three classmates spent money at the school supplies store mark spent 0.5 dollar, andre spent 0.45 dollar, and Raquel spent 0.52
    8·1 answer
  • The average of m, n, and -1 is 0. What is the value of m+n?
    5·1 answer
  • How to make 2 6/11 into a improper fraction and plz show your work my brain is not that smart
    13·1 answer
  • What are the subsets
    15·2 answers
  • Please help me idk this
    6·1 answer
  • Jake’s height is 4.5 feet Explain how to round Jake’s height to the nearest foot
    12·1 answer
  • Can someone please help me? i’m struggling please help
    6·2 answers
  • Hii I need the 7th and 8th question asap will mark brainliest 100% to who ever answers first and right thank you
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!