Answer:
brainly
Explanation:
cuz yeah its the best app ever tbh
Answer:
int SmallestNumber(int num1, int num2, int num3){
int smallest;
if (num1 >num2){
smallest=num2;
}
else {
smallest=num1;
}
if(smallest <num3){
smallest=num3;
}
}
int LargestNumber(int num1, int num2, int num3){
int largest;
if (num1 <num2){
largest=num2;
}
else {
largest=num1;
}
if(largest>num3){
largest=num3;
}
}
void main(){
int num1,num2,num3;
printf("enter values");
scanf("%d%d%d",&num1,&num2,&num3);
int smallest=SmallestNumber(num1,num2,num3);
int largest=LargestNumber(num1,num2,num3);
}
Explanation:
we are comparing first two numbers and finding largest among those. After getting largest comparing that with remaining if it is greater then it will be largest of three. Same logic applicable to smallest also
Wait why do you think it’s bad?
Answer:
The answer is 6.24 years
Explanation:
Given that,
let estimated year is "a" = 10 year
let standard deviation of year is " b" = 2 year
so,
using the normal standard table
P(z<z) = 3 %
P(z<z) = 0.03
P(z< - 1.881) = 0.03
than, z = -1.881
using z-score formula
X = zb + a
X = -1.881 * 2 + 10
X = 6.24 year
