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bagirrra123 [75]
3 years ago
15

TUV = 9x + 1 TUW = 7x-9 WUV 5x-11

Mathematics
2 answers:
bazaltina [42]3 years ago
6 0
9x + 1 + 7x - 9 = 5x - 11
16x - 8 = 5x - 11
11x - 8 = -11
11x = -3
-3/11 = x
enot [183]3 years ago
6 0

Answer:

7

Step-by-step explanation:

9x + 1 = 7x - 9 + 5x - 11

9x + 1 = 12x - 20

9x + 1 - 1 = 12x - 20 - 1

9x = 12x - 21

9x - 12x = 12x - 12x -21

-3x = -21

-3x/3 = -21/-3

x = 7

Hope that helps!

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So, Percentage of change in erasers sold from May to June is given by

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Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
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Answer:

T = 3.967 C

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Density = mass / volume

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   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

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-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

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D = 1/0.001 = 1000 kg/m3

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