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3 years ago

Please help! I am not sure how to set this up or what it is really even asking. (#2)

Mathematics

1 answer:

vladimir2022 [97]3 years ago

8 0

I think they have no points in common because A or B aren't part of CD. AC would share a point with CD. The point they would share is C. THE ANSWER IS B.

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What is an equation of the line with slope 3 that goes through point (-1/2,5/2)?

svetoff [14.1K]

Y= 3x+4 an equation of the lien with slope 3 that goes through point of (-1/2, 5/2)

3 0

3 years ago

Is it more efficient to solve -3x+y=1 for x?why or why notes

lara31 [8.8K]

Answer:

x = y/3 - 1/3

Step-by-step explanation:

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2 years ago

Which is the equation in slope-intercept form for the line that passes through (3, 7)

quester [9]

Answer:

$y = - \frac{5}{3} x + 12$

Step-by-step explanation:

First, rewrite the given equation in the form of y=mx+c.

m is the gradient while c is the y-intercept.

3x-5y=8

5y= 3x -8

$y = \frac{3}{5} x - \frac{8}{5}$

Thus, the gradient of the given equation is ⅗.

The product of the gradients of perpendicular lines is -1.

(gradient of line)(⅗) = -1

gradient of line= -1 ÷⅗

gradient of line= $- \frac{5}{3}$

$y = - \frac{5}{3} x + c$

To find the value of c, substitute a coordinate.

When x=3, y=7,

$7 = - \frac{5}{3} (3) + c$

7= -5 +c

c= 7+5

c= 12

Hence, the equation of the line is $y = - \frac{5}{3} x + 12$ .

6 0

3 years ago

Maggie drew triangle and then triangle . Triangle is congruent to triangle only if ∠ is equal to what value?

Phantasy [73]

Answer:

Angle ABE = 58

Step-by-step explanation:

This would fulfill the AAA theorem, or 3 angles needing to be congruent. We got 58 by subtracting 89 and 62 from 180, then multiplying that answer by 2 (because it occupies both triangles).

7 0

2 years ago

Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).

QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

$\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}$

Using the section formula expressed as

$[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]$

In this case,

$\begin{gathered} m=1 \\ n=2 \end{gathered}$

where

$\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}$

Thus, by substitution, we have

$\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}$

Hence, the y-coordinate of the point P is

$0$

8 0

1 year ago