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dimulka [17.4K]
3 years ago
12

A coworker asks your opinion about how to minimize ActiveX attacks while she browses the Internet using Internet Explorer. The c

oworker recalls there is a setting in the Internet Options dialog box to prompt the user before downloading ActiveX controls, but can’t remember which tab to use.
Which of the following tabs will you suggest to the coworker?

Security tab

Privacy tab

General tab

Programs tab
Computers and Technology
1 answer:
uysha [10]3 years ago
8 0

Answer:

Security Tab is the correct answer.

Explanation:

The Security Tab will enable the users to authorize anyone to use that file or directory.Many clients deleted the security tab because After that nobody can alter the security privileges on the device.

  • With the help of the Security tab, we will minimize the ActiveX attacks on Internet Explorer. This option is available in the Internet Options of the dialog box.
  • Other options are incorrect because they are not related to a given scenario.
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You do not need to use any functions beyond the main function in this problem. Initialize an array of int with the values: 4, 6,
zheka24 [161]

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

   

    int[] arr = {4, 6, 9, 12};

    int sum = 0;

   

    for(int i=0; i<arr.length; i++){

        sum += arr[i];

    }

   

    for(int i=0; i<arr.length; i++){

        System.out.print(arr[i] + " ");

    }

    System.out.println("");

 System.out.println("The sum of the numbers: " + sum);

}

}

Explanation:

* The code is written in Java.

- Initialize the array with the given numbers

- Initialize the <em>sum</em> variable as zero

- Calculate the sum in the first for loop

- Print the numbers in the second for loop

- Print the <em>sum</em>

4 0
3 years ago
Create a method called randomValues that uses a while loop to generate a random number between 1-25 until the value 10 is genera
ahrayia [7]

Answer:

The method in Java is as follows:

public static void randomValues(){

    Random r = new Random();

    int sentinel = 10;

    int randNum = r.nextInt(24) + 1;

    while(randNum!=sentinel){

        System.out.print(randNum+" ");

        randNum = r.nextInt(24) + 1;

    }

    System.out.print(sentinel);

}

Explanation:

This defines the method

public static void randomValues(){

This creates a random object, r

    Random r = new Random();

This sets the sentinel value to 0

    int sentinel = 10;

This generates a random number

    int randNum = r.nextInt(24) + 1;

This loop is repeated until the the random number is 10

    while(randNum!=sentinel){

Print the generated number

        System.out.print(randNum+" ");

Generated another random number

        randNum = r.nextInt(24) + 1;     }

Print the sentinel (i.e. 10)

    System.out.print(sentinel);

}

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3 years ago
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Answer:

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