You can probably refresh or log out or something.
The steps I would take are 1. Making a strong password with symbols and numbers. 2. I will set up a 2 way authentication ther for if someone would be trying to hack me I would get an alert in order to stop the attempt. 3 I will not use the same password each time.
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

⇒ t = 8.7*10⁻⁴ sec.
The code that remove duplicate is as follows:
def remove_duplicate(mylist):
mylist = list(dict.fromkeys(mylist))
return mylist
print(remove_duplicate([1, 1, 2, 3, 3, 5, 6, 7]))
<h3>Code explanation</h3>
The code is written in python.
- we defined a function named "remove_duplicate" and it accept the parameter "mylist".
- The variable "mylist" is used to store the new value after the duplicate vallues has been removed.
- Then, wed returned mylist.
- Finally, we call the function with the print statement . The function takes the required parameter.
learn more on python here: brainly.com/question/21126936