Answer:
P(1, π/4)
P(-1, π/4)
P(4, 5π/6)
P(-4, 5π/6)
Step-by-step explanation:
Knowing the formulas
r = √(x²+y²)
θ = Arctg (y/x)
we have
a) P(1, 1)
i)
r = √(1²+1²) = +1
r = +1
θ = Arctg (1/1) = π/4
P(1, π/4)
ii) r = √(1²+1²) = -1
r = -1
θ = Arctg (1/1) = π/4
P(-1, π/4)
b) P(2√3, -2)
i)
r = √((2√3)²+(-2)²) = +4
r = +4
θ = Arctg (-2/2√3) = 5π/6
P(4, 5π/6)
ii)
r = √((2√3)²+(-2)²) = -4
r = -4
θ = Arctg (-2/2√3) = 5π/6
P(-4, 5π/6)
Y=2/3x-2
to find intercepts, substitute 0 into y and solve for x = x intercept is (3,0) and repeat for y. substitute 0 into x to get y intercept of (0,-2)
Pen=x
Pencil=y
y+0.15=x
y+x=0.69
y+y+0.15=0.69
2y=0.69-0.15
2y=0.54
y=0.54/2
y=0.27 pencils
y+0.15=x
0.27+0.15=x
0x=0.42 pen
150 pencils x0.27=40.5$
225 pens x 0.42=94.5$
Total 40.5$ + 94.50$=135 $
Supplier is right about a priče.
Answer:
1st statement is true.
2nd statement is false.
3rd statement is true.
Step-by-step explanation:
We have been given two inequalities and we are asked to find out whether the given statements are true or false.
represents balance of account A and
represents balance of account B.
1. We can see from our inequalities that Jeremiah initially invested $100 in account A and $50 in account B. Therefore, 1st statement is true.
2. The rate at which balance of account A grows is 1.2 and rate for account B is 1.23. Therefore, 2nd statement is false.
3. We can find total amount Jeremiah invested in two accounts by adding initial investment of both accounts, that is 100+50=150 . Therefore, 3rd statement is true.