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navik [9.2K]
2 years ago
10

Skskskskskssksk!!!!!!11 HELP PLEASE

Mathematics
1 answer:
salantis [7]2 years ago
7 0

Answer:

-8.21

Step-by-step explanation:

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Suppose customers in a certain queue are served one at a time sequentially, that the time for each individual customer is Expone
alexandr402 [8]

Answer:

The shape and rate parameters are \frac{1}{12} and 3.

Step-by-step explanation:

Let <em>X</em> = service time for each individual.

The average service time is, <em>β</em> = 12 minutes.

The random variable follows an Exponential distribution with parameter, \lambda=\frac{1}{\beta}=\frac{1}{12}.

The service time for the next 3 customers is,

<em>Z</em> = <em>X</em>₁ + <em>X</em>₂ + <em>X</em>₃

All the <em>X</em>_{i}'s are independent Exponential random variable.

The sum of independent Exponential random variables is known as a Gamma or Erlang random variable.

The random variable <em>Z</em> follows a Gamma distribution with parameters (<em>α</em>, <em>n</em>).

The parameters are:

\alpha =\lambda=\frac{1}{12}\\n=3

Thus, the shape and rate parameters are \frac{1}{12} and 3.

5 0
3 years ago
Put together, Dulcina and Tremaine have 129 total matchbooks. Tremaine's collection has 39 fewer matchbooks in it than Dulcina's
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Answer:

Let the Dulcina's collection be 'x'

Let the Tremaine collection be 'x-39'

x + x - 39 =129

2x = 129 +39

2x = 168

x = 168/2

x = 84

Dulcina's collection = x = 84

Tremaine's collection = x - 39 = 84 - 39 = 45

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2 years ago
Difference between x and y?
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