Call the point of intersection of the diagonals point X.
Each base is the hypotenuse of an isosceles right triangle whose sides are the diagonals and whose 90° angle is at X. The altitude of that triangle (⊥ distance to the base from X) is half the length of the hypotenuse. Then the height of the trapezoid is half the sum of the base lengths.
The area of the trapezoid is the product of the height and half the sum of the base lengths, hence is the square of half the sum of the base lengths.
... Area = ((16 cm +30 cm)/2)² = (23 cm)² = 529 cm²
Dy/dx = dy/dt * dt/dx
xy = 4
y + x(dy/dx) = 0 by implicit differentiation.
x(dy/dx) = -y
dy/dx = -y/x
<span>dy/dx = dy/dt * dt/dx dy/dt = -2
</span>
<span>-y/x = -2 * dt/dx
</span>
y/(2x) = dt/dx
dt/dx = y/(2x)
dx/dt = 2x/y
When x = -3, xy = 4, y = 4/x = 4/-3 = -4/3
dx/dt = 2*-3/(-4/3) = -6 *-3/4 = 18/4 = 9/2 = 4.5
dx/dt = 4.5
Answer:
5
Step-by-step explanation:
8*5=40 and then 20 short answer that are 3 each. that makes up the rest of the 60 points
Answer:
The classmate's only error is that the slope of the parallel line should be 3 aswell.
Step-by-step explanation:
Parallel lines always have the same slope to each other
