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Complete Question
A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point
Answer:
a)8.717km
b) 54.146°
Step-by-step explanation:
(a)how far is the boat from its starting point.
We solve this question using resultant vectors
= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)
Where
Rcos θ = x
Rsinθ = y
= (4cos38,4sin38) + (5cos67,5sin67)
= (3.152, 2.4626) + (1.9536, 4.6025)
= (5.1056, 7.065)
x = 5.1056
y = 7.065
Distance = √x² + y²
= √(5.1056²+ 7.065²)
= √75.98137636
= √8.7167296826
Approximately = 8.717 km
Therefore, the boat is 8.717km its starting point.
(b)calculate the bearing of the boat from its starting point.
The bearing of the boat is calculated using
tan θ = y/x
tan θ = 7.065/5.1056
θ = arc tan (7.065/5.1056)
= 54.145828196°
θ ≈ 54.146°
2280 Ft there are 3 feet in a yard
We can write this as
(x - 5)^2 + (y + 3)^2 = r^2
where r = radius
Plugging in the point (2,5) we have
(2-5)^2 + (5+3)^2 = r^2
r^2 = 9 + 64 = 73
so the required equation is
(x - 5)^2 + (y + 3)^2 = 73
Answer:
757,576cents
Step-by-step explanation:
Given
Amount = $10000
Time = 4years
Rate = 8%
n = 1/4 year (compounded quarterly
Using the formula to get the principal
A = P(1+r/n)^nt
10000 = P(1+0.08/0.25)^4(1/4)
10000 = P(1+0.32)
10000= 1.32P
P = 10000/1.32
P = 7575.76
Hence he suppose to invest $7575.76 which is equivalent to 7575.76×100 cents i.e 757,576cents
Answer:
12 pigs and 20 chickens
Step-by-step explanation:
Chicken = 2 legs
Pig = 4 legs
(15 * 4) + (17 * 2) = 88 NO
(12 * 4) + (20 * 2) = 88 Yes, and 12 + 20 = 32
