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Nonamiya [84]
3 years ago
9

Solve this @ineedhelplsss

Mathematics
1 answer:
Brut [27]3 years ago
8 0
4^2(x+6)^2-6^2=4x-6+2x^2\ \ \ |use\ (a+b)^2=a^2+2ab+b^2\\\\16(x^2+12x+36)-36=4x-6+2x^2\\\\16x^2+192x+576-36=4x-6+2x^2\\\\16x^2-2x^2+192x-4x+540+6=0\\\\14x^2+188x+546=0\ \ \ \ |divide\ both\ sides\ by\ 2\\\\7x^2+94x+273=0\\\\a=7;\ b=94;\ c=273\\\Delta=b^2-4ac\to\Delta=94^2-4\cdot7\cdot273=8836-7644=1192 \ \textgreater \  0\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{1192}=\sqrt{4\cdot298}=\sqrt4\cdot\sqrt{298}=2\sqrt{289}

x_1=\dfrac{-94-2\sqrt{298}}{2\cdot7}=\dfrac{-47-\sqrt{298}}{7}\\\\x_2=\dfrac{-94+2\sqrt{298}}{2\cdot7}=\dfrac{-47+\sqrt{298}}{7}
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Answer:

see explanation

Step-by-step explanation:

(a)

Given

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Consider the factors of the product of the constant term ( 1) and the coefficient of the k² term (+ 2) which sum to give the coefficient of the k- term (- 3)

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1(1 - k) - 2k(1 - k) ← factor out (1 - k) from each term

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1 - 3k + 2k² = (1 - k)(1 - 2k) and

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(b)

Given

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= 2a(x - 2y) + 3b(x - 2y) ← factor out (x - 2y) from each term

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8 0
3 years ago
Please answer 4-8 much appreciated!
Luba_88 [7]

For 6 points, answering 5 questions is a rip-off.

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haha sike get noob

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2 years ago
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Step-by-step explanation:

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3 years ago
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2 years ago
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