All categories

3 years ago

Which is the graph of the equation y-1=2/3(x-3)? PLEASE ANSWER ASAP

Mathematics

2 answers:

alexgriva [62]3 years ago

8 0

Answer:

Graph #1

Step-by-step explanation:

Compare your

y - 1 = (2/3)(x - 3) to

y - k = m(x - h). We see that k = 1 and h = 3.

Thus, (1, 3) is a point on the graph. This matches Graph #1.

Note: Graph #1 and Graph #3 appear to be the same. Why?

strojnjashka [21]3 years ago

7 0

<h2>Answer:</h2>

The graph of the equation is:

Graph 1

<h2>Step-by-step explanation:</h2>

The equation is given by:

$y-1=\dfrac{2}{3}\times (x-3)$

Now, we will see the point through which the graph passes through.

when x=3 we have:

$y-1=\dfrac{2}{3}\times (3-3)\\\\i.e.\\\\y-1=\dfrac{2}{3}\times 0\\\\i.e.\\\\y-1=0\\\\i.e.\\\\y=1$

i.e. the graph passes through (3,1)

and also when x= -3 we have:

$y-1=\dfrac{2}{3}\times (-3-3)\\\\i.e.\\\\y-1=\dfrac{2}{3}\times -6\\\\i.e.\\\\y-1=2\times -2\\\\i.e.\\\\y-1=-4\\\\i.e.\\\\y=-4+1\\\\i.e.\\\\y=-3$

i.e. the graph passes through (-3,-3)

The graph which satisfies these two points is: Graph 1

You might be interested in

An amusement park's owners are considering extending the weeks of the year that it is opened. The owners would like to survey 10

jeka94

The best way to randomly choose the 100 families would be to allow a random number generator to come up with 100 families within a 50 radius of the amusement park.

Using this method would ensure that it is more randomised & not limited to people who come at a specific time or are in a specific area as well as it not be affected by subconscious bias of people when selecting people to survey.

3 0

3 years ago

Read 2 more answers

-23<br> Simplify your answer as much as possible.<br> =<br> X<br> ?

Murljashka [212]

Answer:

Question is not fully addressed

Step-by-step explanation:

Please put the full question otherwise, i cannot answer it

3 0

3 years ago

How do you write 2/4 in percent form

forsale [732]

2 / 4 x 100

= .50 x 100

= 50%

6 0

3 years ago

Read 2 more answers

A probability distribution is a listing of all the outcomes of an experiment and the probability associated with each outcome. T

Novosadov [1.4K]

Answer:

True.

Step-by-step explanation:

A probability distribution is a listing of all the outcomes of an experiment and the probability associated with each outcome. Probability distribution is associated with the following characteristics or properties;

1. The outcomes are mutually exclusive.

2. The list of outcomes is exhaustive, which simply means that the sum of all probabilities of the outcomes must equal one (1).

3. The probability for a particular value or outcome must be between 0 and 1.

Since a probability distribution gives the likelihood of an outcome or event, a single random variable is divided into two main categories, namely;

I. Probability density functions for continuous variables.

II. Discrete probability distributions for discrete variables.

For example, when a coin is tossed, you can only have a head or tail (H or T).

Also, when you throw a die, the only possible outcome is 1/6 and the total probability for it all must equal to one (1).

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

$\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}$

and it follows that

$\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}$

7 0

2 years ago