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Aneli [31]
2 years ago
5

Jermaine’s father owes $6,300 in interest at the end of a 60-month car loan at a 7% simple annual interest rate. What was the or

iginal loan amount?
Mathematics
2 answers:
Katyanochek1 [597]2 years ago
7 0

Answer:

$18,000

Step-by-step explanation:

It is given that the interest amount $6,300

We will calculate the principal amount.

So we use the formula

I = prt

P = Principal amount

r = rate of interest 7% ( 0.07 )

t = time in years 60 months ( \frac{60}{12} years )

6,300 = P × 0.07 × \frac{60}{12}

6,300 = P × 0.07 × 5

6,300 = 0.35P

\frac{6,300}{0.35} = P

P = $18000

The original loan amount was $18,000.  

Sever21 [200]2 years ago
6 0
I = Prt
6300 = P * .07 * (60/12)
6300 = .35P
6300 / .35 = P
18000 = P

$18,000 is the answer you are looking for! I hope this helps! :D
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Answer: x = 15.035677095729 approximately

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=================================================

Explanation:

I'm assuming you want to find the value of x, which your diagram is showing to be the length of segment QR.

If so, then we'll need to find the measure of angle Q first. Using the law of sines, we get the following:

sin(Q)/q = sin(R)/r

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sin(Q) = 13*sin(85)/19

sin(Q) = 0.6816068987

Q = arcsin(0.6816068987) ... or ... Q = 180-arcsin(0.6816068987)

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----------------

Now if Q = 42.9693397461 approximately, then angle P is

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P = 180-42.9693397461-85

P = 52.0306602539

Similarly, if Q = 137.0306602539 approximately, then,

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P = 180-137.0306602539-85

P = -42.0306602539

A negative angle is not possible, so we'll ignore Q = 137.0306602539

----------------

The only possible value of angle P is approximately P = 52.0306602539

Let's apply the law of sines again to find side p, aka segment QR

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19*sin(52.0306602539)/sin(85) = x

x = 15.035677095729

This value is approximate.

Round this value however you need to.

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