<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B9%20%7Bx%7D%5E%7B2%7D%20%7D%20" id="TexFormula1" title=" \sqrt{9 {x}^{2} } " alt=

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SOVA2 [1]

3 years ago

" \sqrt{9 {x}^{2} } " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Firlakuza [10]3 years ago

6 0

The answer would be 3x i believe
hope this helps! if it doesn't, let me know in the comments! have a great day!

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What is the asymptote of the exponential function y = abx + c?

vredina [299]

The correct answer to this question is Choice D: y = c

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7 0

4 years ago

Find the inverse please and thank you

Amanda [17]

The inverse $f^{-1}(x)$ is such that

$f\left(f^{-1}(x)\right) = x$

We have

$f\left(f^{-1}(x)\right) = -9\sqrt{f^{-1}(x) - 8} + 5 = x$

Solve for the inverse.

$-9\sqrt{f^{-1}(x)-8} + 5 = x \\\\ -9\sqrt{f^{-1}(x)-8} = x-5 \\\\ \sqrt{f^{-1}(x)-8} = -\dfrac{x-5}9 \\\\ \left(\sqrt{f^{-1}(x)-8}\right)^2 = \left(-\dfrac{x-5}9\right)^2 \\\\ f^{-1}(x) - 8 = \dfrac{(x-5)^2}{81} \\\\ \boxed{f^{-1}(x) = 8 + \dfrac{(x-5)^2}{81}}$