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AlexFokin [52]
3 years ago
7

X(x + 3) = x^2 + 3x FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF

Mathematics
1 answer:
allsm [11]3 years ago
4 0
X^2+3x=x^2+3x
X=all real numbers
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Fill in the blanks to the picture above
Verdich [7]
The left side was cut out but x will be on top and 5 in the lower square. The last one is the answer.

3 0
3 years ago
We defined the operation of concatenation for sets of strings on p. 10, AB = { XY | X ∈ A and y ∈ B}Are the regular sets closed
lakkis [162]

Answer and Explanation:

Solution: The operation of concatenation for a set of string on p. and the set is

     AB = {XY | X ∈ A and y ∈ B}.

We need to satisfy all these following properties to find out the standard set is closed under concatenation.

1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.

2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.

3- Intersection of two standards set A and B is A∩B is also a regular set member.

4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.

The closure of the regular set is also standard, and the concatenation of traditional sets is regular.

3 0
3 years ago
If 5 slices of pizza cost $5:50 how much does 
kupik [55]

The first thing we must do for this case is to define variables.

We have then:

x: number of slices

y: total cost

We write the linear function that relates the variables.

We have then:

y = (\frac{5.50}{5}) * x

Then, we evaluate the number of slices to find the total cost.

-two slices cost:

We substitute x = 2 in the given equation:

y = (\frac{5.50}{5}) * 2\\y = 2.2

Answer:

two slices = 2.2 $

-ten slices cost:

We substitute x = 10 in the given equation:

y = (\frac{5.50}{5}) * 10\\y = 11

Answer:

ten slices = 11 $

-half a slice cost:

We substitute x = 1/2 in the given equation:

y = (\frac{5.50}{5}) * \frac{1}{2}\\y = 0.55

Answer:

half a slice = 0.55 $

6 0
3 years ago
Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t
DerKrebs [107]

Isolate one variable in the system of equations. Use substitution to create a one-variable equation. Then, set the quadratic equation equal to zero and find the discriminant. If the discriminant is negative, then there are no real number solutions. If the discriminant is zero, then there is one real number solution. If the discriminant is positive, then there are two real number solutions.

4 0
3 years ago
Read 2 more answers
Given the functions f(x) = 3(0.56)^x and g(x) = 6(4)^x
rodikova [14]
A)  f(x) is decreasing because the base is less than 1.
      0.56 is close to 0.5, so its like saying that you are taking half each time, therefore the value is getting smaller.

g(x) is increasing because the base is greater than 1.
you are multiplying by 4 each time, making the value bigger.


B )  The y-intercept is where x=0.
      Anything to the '0' power is 1. Therefore the y-intercept is equal to the coefficient in front of each function.
    f(x) = 3 ,   g(x) = 6


C)  Just plug in x=4 to each function in a calculator.
 f(4) = 0.295
g(4) = 1536
7 0
3 years ago
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