Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t
2 answers:
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Answer:
So on this case the 80% confidence interval would be given by (3.003;3.297)
And the margin of error is given by:
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean
population mean (variable of interest)
represent the population standard deviation
n=11 represent the sample size
Solution to the problem
The confidence interval for the mean is given by the following formula:
(1)
Since the Confidence is 0.80 or 80%, the value of and
, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NOR.INV(0.1,0,1)".And we see that
Now we have everything in order to replace into formula (1):
So on this case the 80% confidence interval would be given by (3.003;3.297)
And the margin of error is given by:
Answer:
The coordinate of B is (6,0)
Step-by-step explanation:
Given;
coordinate of A = (-4,2) = (x₁, y₁)
coordinate of M = (1,1)
let coordinate of B = (x₂, y₂)
Mid-point is given by;
Therefore, the coordinate of B is (6,0)