A giant star is a star with substantially larger radius and luminosity than a main-sequence (or dwarf) star of the same surface temperature. They lie above the main sequence (luminosity class V in the Yerkes spectral classification) on the Hertzsprung–Russell diagram and correspond to luminosity classes II and III.
7 - 15 x n
good luck XD XD
A triangle can not be drawn with these side lengths. This is because when you add 2cm+8cm, it is not more than 11 cm.
Answer:
4a + 2b/3
Step-by-step explanation:
focus on 8b/12 first:
factor 8b/12 by 4 ---> 8b/12 = 4(2)b/4(3) ----> cancel 4 in the denominator and the nominator ---> 8b/12 = 4(2)b/4(3) = 2b/3
then, go back to 4a:
4a is in its simplest form, it can't be factor
therefore, plus 4a and 2b/3 = 4a + 2b/3
They tell you that the length is 7 inches and that it is 2 inches more than the width therefore you can conclude that: length = 7 and the width = 5
you can plug the values given into the formula listed below:
A = lw
A = 7 x 5
A = 35
hope this helps :)
