Find the length of an arc intercepted by a central angle of 0.769 radian on a circle with radius 11.4cm????? PLEASE HELP SHOW AL
L WORK
2 answers:
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The answer is 7.9306
Using the formula in the attached:
Where: xi = sample value; μ = sample mean; n = sample size
1.) Calculate the mean first:
μ = 12.0 + 18.3 + 29.6 + 14.3 + 27.8 / 5
= 102 / 5
μ = 20.4
2.) Using the mean, calculate (xi - μ)² for each value:
(12.0 - 20.4)² = 70.56
(18.3 - 20.4)² = 4.41
(29.6 - 20.4)² = 84.64
(14.3 - 20.4)² = 37.21
(27.8 - 20.4)² = 54.76
3.) Sum the squared differences and divide by n - 1.
μ = 70.56 + 4.41 + 84.64 + 37.21 + 54.76
= 251.58 / 5-1
μ = 62.895 (this is now called sample variance)
4.) Get the square root of the sample variance:
√62.895 = 7.9306
Using the formula in the attached:
Where: xi = sample value; μ = sample mean; n = sample size
1.) Calculate the mean first:
μ = 12.0 + 18.3 + 29.6 + 14.3 + 27.8 / 5
= 102 / 5
μ = 20.4
2.) Using the mean, calculate (xi - μ)² for each value:
(12.0 - 20.4)² = 70.56
(18.3 - 20.4)² = 4.41
(29.6 - 20.4)² = 84.64
(14.3 - 20.4)² = 37.21
(27.8 - 20.4)² = 54.76
3.) Sum the squared differences and divide by n - 1.
μ = 70.56 + 4.41 + 84.64 + 37.21 + 54.76
= 251.58 / 5-1
μ = 62.895 (this is now called sample variance)
4.) Get the square root of the sample variance:
√62.895 = 7.9306
Answer:
136
Step-by-step explanation:
Well if you find the lateral area (the area of the rectangles on the sides) to get 112, so you just need to add that to the triangles and for those (they add up to 36) you can just use the formula for the area of a triangle, which is .
Hope this helps :)