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-BARSIC- [3]
3 years ago
7

Find the length of an arc intercepted by a central angle of 0.769 radian on a circle with radius 11.4cm????? PLEASE HELP SHOW AL

L WORK

Mathematics
2 answers:
KIM [24]3 years ago
7 0
0.769/2pi=what fraction of circle you are having

area=pir^2
area=pi11.4^2
area=pi129.96

what fraction

0.769/2pi times 129.96pi=49.96962 cm^2

the area is 49.96962 cm^2
ELEN [110]3 years ago
6 0
I hope this helps you

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lina2011 [118]
Answer:
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Step-by-step explanation:
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5 0
2 years ago
Surface area???????????
MAVERICK [17]

Answer:

The option B is the correct answer. 79.18 m²

Step-by-step explanation:

Surface area = Base area +  Lateral surface area

Area of triangle = bh/2

b - base and h - height

<u>To find the base area</u>

We can consider the base is a hexagon.

A regular hexagon is a combination of 6 equilateral  triangle

Base area = 6 * area of triangle

base b = 3

<u>To find the height</u>

h =√[(6.2)² - (5.6)₂] = 2.7

Area of triangle bh/2 = (3 * 2.7)/2 = 3.99

Area of base = 23.95

To find lateral surface area

Lateral surface area = 6 * area of triangle

Area of triangle = bh/2 =(3 *6.2)/2 = 9.3

Lateral surface area = 6 * 9.3 = 55.8

<u>To find the total surface area </u>

Total surface area = Base area + lateral surface area = 23.95 + 55.8

= 79.75 m²

Therefore the option B is the correct answer. 79.18 m²

7 0
3 years ago
What is (64x^2y^3)-1/2 as radical expression?
oksano4ka [1.4K]

Answer:

\frac{1}{8xy \sqrt{y} }

Step-by-step explanation:

(64 {x}^{2}  {y}^{3} )^{  - \frac{ 1 }{2} }  \\  \\  =  \frac{1}{(64 {x}^{2}  {y}^{3} )^{\frac{ 1 }{2} } }  \\  \\  =  \frac{1}{ \sqrt{64 {x}^{2}  {y}^{3}} }  \\  \\  =  \frac{1}{ \sqrt{ {(8xy)}^{2} y} }  \\  \\  =  \frac{1}{8xy \sqrt{y} }

3 0
2 years ago
Please help due asap
Nadusha1986 [10]
Answer:5
Explanation:Pythagorean Theorem
4 0
2 years ago
Pls help with this problem
madam [21]

Step-by-step explanation:

every triangle inscribed into a circle with the baseline being a diameter of the circle must be a right-angled triangle.

therefore,

angle XVY = 90°.

for VY we can use Pythagoras

c² = a² + b²

with c being the Hypotenuse (the line opposite of the 90° angle, in our case XY).

XY = 2×ZY = 2×17 = 34.

so,

34² = 30² + VY²

VY² = 34² - 30² = 1156 - 900 = 256

VY = 16

6 0
2 years ago
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