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3 years ago

An african lion weighs 450 pounds.What is its weight in ounces?

Mathematics

1 answer:

DIA [1.3K]3 years ago

7 0

Since there are 16 ounces in 1 pound. You'd multiply 450(pounds)*16(ounces) which would equal 7,200 ounces.

Hope this helped : )

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The sum of two numbers is 61. If the larger number is seven less than three times the smaller number, find both numbers.

Julli [10]

Answer:

x = 17, y = 44

Step-by-step explanation:

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2 years ago

2/3 of 16 ...........................

maxonik [38]

Answer:

2/3 * 16

32/3 = 10.66

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5 0

3 years ago

Read 2 more answers

A plane intersects both nappes of a double-napped cone but does not go through the vertex of the cone. What conic section is for

lisabon 2012 [21]

When a plane intersects both nappes of a double-napped cone but does not go through the vertex of the cone, the conic section that is formed by the intersection is a curve known as hyperbola.
The standard form of the equation of the hyperbola is shown below:
[(x-h)^2/a^2]-[(y-k)^2/b^2]=1 (Horizontal axis)
[(y-k)^2/a^2]-[(x-h)^2/b^2]=1 (Vertical axis)
Therefore, the answer is: Hyperbola.

3 0

3 years ago

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago

How do you find the least common multiple of two numbers?

ozzi

Answer:

Step-by-step explanation:

Let's say we wanted to find the LCM of 6 and 8.

First, write the prime factorization of both:

6 = 2×3

8 = 2³

Let's include all the exponents:

6 = 2¹×3¹

8 = 2³×3⁰

The LCM needs to have the prime factors with the highest exponents.

So we need prime factors of 2 and 3. The exponent of the 2 will be three, and the exponent of the 3 will be one.

LCM = 2³×3¹

LCM = 24

3 0

3 years ago