I would say the third one would be the correct or the second one
-35.248711306 Hope this helps:)
I think it’s c but don’t go with me see if others answer with a different answer :)
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The standard form of the equation of a circumference is given by the following expression:
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![(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D%20%5C%5C%20%5C%5C%20where%20%5C%20%28h%2C%20k%29%20%5C%20is%20%5C%20the%20%5C%20center%20%5C%20of%20%5C%20the%20%5C%20circumference%20%5C%20and%20%5C%20r%20%5C%20the%20%5C%20radius)
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On the other hand,
the general form is given as follows:
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![x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%2By%5E%7B2%7D%2BDx%2BEy%2BF%3D0%20%5C%5C%20%5C%5C%20where%3A%20%5C%5C%20D%3D-2h%2C%20%5C%20E%3D-2k%2C%20%5C%20F%3Dh%5E%7B2%7D%2Bk%5E%7B2%7D-r%5E%7B2%7D)
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In this way, we can order the mentioned equations as follows:
Equations in Standard Form: </span>
Equations in General Form:
![\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0](https://tex.z-dn.net/?f=%5Cbold%7B1%29%7D%20%5C%20x%5E%7B2%7D%2By%5E%7B2%7D-4x%2B12y-20%3D0%20%5C%5C%20%5Cbold%7B2%29%7D%20%5C%20x%5E%7B2%7D%2By%5E%7B2%7D%2B6x-8y-10%3D0%20%5C%5C%20%5Cbold%7B3%29%7D%20%5C%203x%5E%7B2%7D%2B3y%5E%7B2%7D%2B12x%2B18y-15%3D0%20%5C%5C%20%5C%5C%20If%20%5C%20we%20%5C%20divide%20%5C%20this%20%5C%20equation%20%5C%20by%20%5C%203%2C%20%5C%20the%20%5C%20equation%20%5C%20becomes%3A%20%5C%5C%20x%5E%7B2%7D%2By%5E%7B2%7D%2B4x%2B6y-5%3D0%20%5C%5C%20%5C%5C%20%5Cbold%7B4%29%7D%20%5C%205x%5E%7B2%7D%2B5y%5E%7B2%7D-10x%2B20y-30%3D0%20%5C%5C%20%5C%5C%20If%20%5C%20we%20%5C%20divide%20%5C%20this%20%5C%20equation%20%5C%20by%20%5C%205%2C%20%5C%20the%20%5C%20equation%20%5C%20becomes%3A%20%5C%5C%20x%5E%7B2%7D%2By%5E%7B2%7D-2x%2B4y-6%3D0%20%5C%5C%20%5C%5C%20%5Cbold%7B5%29%7D%20%5C%202x%5E%7B2%7D%2B2y%5E%7B2%7D-24x-16y-8%3D0%20%5C%5C%20%5C%5C%20If%20%5C%20we%20%5C%20divide%20%5C%20this%20%5C%20equation%20%5C%20by%20%5C%202%2C%20%5C%20the%20%5C%20equation%20%5C%20becomes%3A%20%5C%5C%20x%5E%7B2%7D%2By%5E%7B2%7D-12x-8y-4%3D0%20)
![\bold{6)} \ x^{2}+y^{2}+2x-12y](https://tex.z-dn.net/?f=%5Cbold%7B6%29%7D%20%5C%20x%5E%7B2%7D%2By%5E%7B2%7D%2B2x-12y)
So let's match each equation:
Then, its general form is:
<em><u>First. a) matches 5)
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![\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20](https://tex.z-dn.net/?f=%5Cbold%7BFrom%20%5C%20b%29%7D%20%5C%5C%20%5C%5C%20%28h%2Ck%29%3D%282%2C-6%29%2C%5C%20r%3D2%5Csqrt%7B15%7D%20%5C%5C%20D%3D-4%2C%20%5C%20E%3D12%20%5C%5C%20F%3D-20)
Then, its general form is:
<em><u>Second. b) matches 1)
</u></em>
Then, its general form is:
<em><u>Third. c) matches 3)</u></em>
Then, its general form is:
<em><u>Fourth. d) matches 6)</u></em>
Answer:
C
Step-by-step explanation:
the volume of the cylinder is 3769.91
the volume of the cube is 1000
so the cylinder's volume is clearly larger than the cube's volume.