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mamaluj [8]
3 years ago
6

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unknown

endpoint. Apply the midpoint formula, and solve the two equations for x and y) midpoint(-23,10) endpoint (-17,7)
Mathematics
1 answer:
Naily [24]3 years ago
3 0
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -17}}\quad ,&{{ 7}})\quad 
%  (c,d)
&({{ x}}\quad ,&{{ y}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)

\bf \left( \cfrac{x-17}{2}~,~\cfrac{y+7}{2} \right)=\stackrel{\textit{midpoint}}{(-23,10)}\implies 
\begin{cases}
\cfrac{x-17}{2}=-23\\\\
x-17=-46\\
\boxed{x=-29}\\
----------\\
\cfrac{y+7}{2}=10\\\\
y+7=20\\
\boxed{y=13}
\end{cases}
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Find two consecutive odd integers such that 65 more than the lesser is four times the greate
lyudmila [28]
Let the lesser number be x  and y the greater. Then

x + 65 = 4y ,  Also

y - x =  2
Adding:-

y + 65 = 4y + 2
63 = 3y
y = 21
and
x = 21-2 = 19

Answer the 2 odd numbers are 19 and 21.


8 0
3 years ago
CAN SOMEBODY PLZZ HELP IM STUDYING FOR A MATH TEST PLLZZZ HELP!!! Thank You!
KatRina [158]

Answer:

46

Step-by-step explanation:

just do -4x-4=16 then 6x5=30 than add 16+30 =46

8 0
3 years ago
Simplify the cube root in simplest radical form.<br> 9x374<br> Please help
algol [13]

Answer:

D. xy\sqrt[3]{9y}

Step-by-step explanation:

\sqrt[3]{9x^3y^4}

\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}

The \sqrt[3]{x^3} cancels out to become x:

\sqrt[3]{9}x\sqrt[3]{y^4}

Split the y^4=y*y^3

\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}

\sqrt[3]{y^3} =y

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Put the cube root of y and cube root of 9 together:

xy\sqrt[3]{9y}

6 0
4 years ago
X-Y=5, 6X-6Y =?
denis-greek [22]

Answer:

<u>Yes, it is 30</u>

Step-by-step explanation:

And yes, you thought it through correctly.  6(X-Y) = 6*5

6(X-Y) = <u>30</u>

3 0
3 years ago
Read 2 more answers
Using the quadratic formula to solve x^2=5-x what are the values of x?
kenny6666 [7]
A
you have to solve x^2+x-5=0
So x=(-1 +/- sqrt(1^2+4*1*5))/2
x=(-1 +/- sqrt(21))/2
3 0
3 years ago
Read 2 more answers
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