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gregori [183]
3 years ago
9

A juggler throws a ball into the air from a height of 5 ft with an initial vertical velocity of 16 ft/s. The function that model

s the height h of the ball in feet t seconds after the ball is thrown is h(t) = -16t2 + 16t + 5. How long does the juggler have to catch the ball before it hits the ground?
Mathematics
1 answer:
photoshop1234 [79]3 years ago
5 0
1.25 seconds to catch the ball before it hits the ground :D hope i helped
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svetoff [14.1K]

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We have a slope and a point, this way, we do not need to find the slope using two points. We can find the line using the Slope Form to turn it into Slope-Intercept Form, also known as "y = mx + b". We can use the Slope Form which is "y - y1 = m(x - x1)". A coordinate is "(x,y)", so that means, "(-1,4)" means that x = -1 and y = 4. We can substitute y1 for 4 and x1 for -1, and m for -5 since m is the slope. Plugging that information into the Slope Form Formula we get "y - 4 = -5(x - (-1))". We know that a negative with a negative turn positive, so we can use this information to change the formula to "y - 4 = -5(x + 1)". Now we distribute and simplify, these steps are shown below.

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