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aivan3 [116]
3 years ago
6

I need to solve cy−7=5d+3y for y, any help?

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0
Given cy - 7 = 5d + 3y, we solve for y as follows:

cy - 3y = 5d + 7

y(c - 3) = 5d + 7

y = (5d + 7) / (c - 3)
inysia [295]3 years ago
5 0

For this case we have the following equation:

cy-7 = 5d + 3y

We must clear the value of y.

For this, we follow the following steps:


1) We place the variables on one side of the equation and the constant terms on the other side of the equation:

cy-3y = 5d + 7


2) We make the common factor "y" on the left side of the equation:

y(c-3) = 5d + 7


3) We move to divide c-3 on the right side of the equation:

y = \frac{5d + 7 }{c-3}


Answer:

The value of y is given by:

y = \frac{5d + 7 }{c-3}

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So here, we can write 1 and 5/8 as the improper fraction 13/8 and we can write 5 and 1/7 as the improper fraction 36/7.

So here, we have 13/8 ÷ 36/7.

Dividing by a fraction is the same as multiplying by the reciprocal of that fraction.

So here, 13/8 ÷ 36/7 is the same as 13/8 × 7/36.

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