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aivan3 [116]
3 years ago
6

I need to solve cy−7=5d+3y for y, any help?

Mathematics
2 answers:
iVinArrow [24]3 years ago
8 0
Given cy - 7 = 5d + 3y, we solve for y as follows:

cy - 3y = 5d + 7

y(c - 3) = 5d + 7

y = (5d + 7) / (c - 3)
inysia [295]3 years ago
5 0

For this case we have the following equation:

cy-7 = 5d + 3y

We must clear the value of y.

For this, we follow the following steps:


1) We place the variables on one side of the equation and the constant terms on the other side of the equation:

cy-3y = 5d + 7


2) We make the common factor "y" on the left side of the equation:

y(c-3) = 5d + 7


3) We move to divide c-3 on the right side of the equation:

y = \frac{5d + 7 }{c-3}


Answer:

The value of y is given by:

y = \frac{5d + 7 }{c-3}

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Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0
3 years ago
HURRY ASAP IM ABT TO TURN THIS IN
Lina20 [59]
The answer would be -1
4 0
2 years ago
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The diameter of a circle measures 26 mm what is the circumference of the circle
nasty-shy [4]
The circumference is 81.68 mm. C= 2pi(r)

3 0
3 years ago
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{(4z-7,z-4,z) |z is any real number} z=-5
weeeeeb [17]

The set when z = -5 is {-27, -9, -5}

<h3>How to determine the set elements?</h3>

The set is given as:

{(4z-7,z-4,z) |z is any real number}

When z=-5, we have:

4z - 7 = 4(-5) - 7 = -27

z - 4 = -5 - 4 = -9

z = -5

So, we have:

{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}

Hence, the set when z = -5 is {-27, -9, -5}

Read more about sets at:

brainly.com/question/8053622

#SPJ1

4 0
2 years ago
|x|-13=-3 solve the equation​
galina1969 [7]

Answer:

x=10\\x=-10

Step-by-step explanation:

|x|-13=-3\\|x|=-3+13\\|x|=10

x=10\\x=-10

5 0
2 years ago
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