All categories

3 years ago

Pedro simplified 4/7 5/8 his work is shown below identify where he made his error

Mathematics

1 answer:

motikmotik3 years ago

6 0

4/7 cannot be simplified anymore. 5/8 can't be simplified either.

You might be interested in

write the equation of the parabola and a vertex form and standard form given the following information

beks73 [17]

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

(9)

Here (h, k) = (3, - 2), thus

y = a(x - 3)² - 2

To find a substitute (2, 3) into the equation

3 = a(2 - 3)² - 2 ( add 2 to both sides )

5 = a(- 1)² = a , then

y = 5(x - 3)² - 2 ← in vertex form

y = 5(x² - 6x + 9) - 2

= 5x² - 30x + 45 - 2

y = 5x² - 30x + 43 ← in standard form

(10)

Here (h, k) = (2, - 5), thus

y = a(x - 2)² - 5

To find a substitute (5, 4) into the equation

4 = a(5 - 2)² - 5 ( add 5 to both sides )

9 = a(- 3)² = 9a ( divide both sides by 9 )

a = 1

y = (x - 2)² - 5 ← in vertex form

y = x² - 4x + 4 - 5

y = x² - 4x - 1 ← in standard form

4 0

3 years ago

Read 2 more answers

a triangles has side lengths of 7, 10 and 11 what is the perimeter of the triangle formed by joining the midpoints of these side

hodyreva [135]

A triangles has side lengths of 7, 10 and 11 what is the perimeter of the triangle formed by joining the midpoints of these sides?

7 0

3 years ago

Find the value of 2 numbers if their sum is 9 and their difference is 1

Sloan [31]

Makes no sense.

p.s i am a fourth grader

5 0

3 years ago

Read 2 more answers

What is estimate 703 and 620 sum

coldgirl [10]

703+620≈1320

first you have to round 703 to 700, because it's an estimation, then you can add 700 to 620, and it'll be easier than 703+620.

3 0

4 years ago

Read 2 more answers

Sergio works at a bakery and needs to cover

Elan Coil [88]

Answer:

The surface area that Sergio needs to frost on each cake is 3,238 square centimeters

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The surface area of the cylindrical cake is equal to the lateral area plus the area of the top of cylinder (remember that the bottom of the cake does not need frosting)

$SA=\pi r^{2}+2\pi r h$

we have

$r=40.2/2=20.1\ cm$ ---> the radius is half the diameter

$h=15.6\ cm$

$\pi=3.14$

substitute the given values

$SA=(3.14)(20.1)^{2}+2(3.14)(20.1)(15.6)$

$SA=1,268.59+1,969.16\\SA=3,237.75\ cm^2$

Round up to the nearest whole number

$SA=3,238\ cm^2$

therefore

The surface area that Sergio needs to frost on each cake is 3,238 square centimeters

5 0

4 years ago