Answer:
h = -9
Step-by-step explanation:
Distribute the 2 to the parentheses:
5h + 2(11 - h) = -5
5h + 22 - 2h = -5
Add like terms:
3h + 22 = -5
3h = -27
h = -9
<span>Equation:
silver + silver = silver
0.45x + 0.60(40-x) = 0.48*40
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45x + 60*40 - 60x = 48*40
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-15x = -12*40
x = (4/5)40
x = 32 lbs (amt of 45% slloy needed)
40-x = 8 lbs (amt of 60% alloy needed)</span>
The simplified expression would be 6m-8n+4p
Answer:
the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
Step-by-step explanation:
Given the data in the question;
we know that;
the coefficient of determination is r²
while the correlation coefficient is defined as r = √(r²)
The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.
Now, given that class attendance explained 16% of the variation in grade index among the students.
so
coefficient of determination is r² = 16%
The correlation coefficient between percent of classes attended and grade index will be;
r = √(r²)
r = √( 16% )
r = √( 0.16 )
r = 0.4
Therefore, the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
