All categories

3 years ago

If the point (-1-5) is reflected across x-axis, whot aro tho coordinates of th new point? ?

Mathematics

1 answer:

Gnoma [55]3 years ago

5 0

Answer:

-1, 5

Step-by-step explanation:

With the graph, when you switch the x axis, you have to make the additive inverse for the y. If Y, additive the X.

You might be interested in

Without solving, determine whether the equation 3 - (x + 1) = 2 - x has one solution, no solutions, or infinitely many solutions

Rudiy27

Answer:

infinite

Step-by-step explanation:

3 0

3 years ago

The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.

ololo11 [35]

Answer: (a) {a, ar, ar², ar³, ar⁴, ar⁵...}, (b) arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

4 0

3 years ago

Standard form of a point that goes through-2,4 and the slope is -1/7

lesantik [10]

<u>Answer:</u>

Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26

<u>Solution:</u>

Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7

Standard form of line passing through point ( a , b ) and having slope m is given by

(y – b) = m ( x – a) --------(1)

In our case given point is ( -2 , 4 ) and slope is -1/7 that means

a = -2 , b = 4 , m = -(1/7)

On substituting given value of a , b and m is equation (1) we get

$(y-4)=\left(-\frac{1}{7}\right)(x-(-2))$

$=>(y-4)=\left(-\frac{1}{7}\right)(x+2)$

=> 7( y - 4 ) = -x – 2

=> 7y + x = -2 + 28

=> x + 7y = 26

Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26

8 0

3 years ago

Is it true that no integers are irrational numbers

vazorg [7]

Yes, irrational number are all numbers that are not rational and all integers are rational numbers

6 0

3 years ago

Read 2 more answers

You already know its another giveaway

nasty-shy [4]

Answer: yay thxs

Step-by-step explanation:

5 0

2 years ago