Answer:
for the cellular respiration the human body needs 1.424 E21 molecules of glucose
Explanation:
mass glucose = 24 g
∴ Mw glucose = 180.156 g/mol
∴ 1 mol ≡ 6.022 E23 molecules
⇒ mol glucose = (24 g)×(mol/180.156 g) = 0.1332 mol glucose
⇒ molecules glucose = (0.1332 mol glucose)×(6.022 E23 molecules/mol)
⇒ molecules glucose = 1.424 E21 molecules
Answer:
Ernest Z. The molarity and mass percent of the vinegar are 0.8393 mol/L and 5.010 %.
Answer:
0.07975 M NaOH
Explanation:
First determine the molarity of your acid, KHP. Convert grams to moles using the MW given and then divide by the volume of water.
0.3175 g KHP • (1 mol KHP / 204.2 g KHP) = 0.001555 mol KHP
0.001555 mol KHP / 0.040 L = 0.03888 M KHP
The reaction between KHP and NaOH is one-to-one, so you can just use M1V1 = M2V2 to solve for M2 (the molarity of NaOH).
M1 = 0.03888 M KHP
V1 = 40 mL
M2 = ? M NaOH
V2 = 19.45 mL NaOH
(0.03888 M KHP)(40 mL) = M2(19.5 mL NaOH)
M2 = 0.07975 M NaOH
When titrating a strong monoprotic acid and KOH at 25 degrees Celcius, the pH will be approximately equal to 7.00. Since a strong acid and a strong base reacts through a neutralization reaction. The pH of a neutral solution is 7.00. <span />