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olga_2 [115]
4 years ago
14

1. Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 50 L against a constant external pressure

of 1.5 atm. (1 L • atm = 101 J)
2. Calculate the work, w, gained or lost by the system when a gas expands from 15 L to 50 L against a constant external pressure of 1.5 atm. (1 L • atm = 101 J +5.3 kJ -7.6 kJ +7.5 kJ -5.3 kJ)
Chemistry
1 answer:
Ira Lisetskai [31]4 years ago
5 0

Answer:

w = -3.8KJ

Explanation:

The work done on a system which is under an external pressure

P = w = - \int\limits^._. {p} \, dV \\w = - PΔV\\\\

P = 1.5 atm

ΔV = 40  − 15 = 25 L

w = - P ΔV = -1.5 (25) = - 37.5 L.atm

w = 37.5 X 101.325  J ≈ − 3800 J = −3.8 KJ

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Answer : Option D) Sodium Chloride.

Explanation : Boiling point is the temperature at which the vapor pressure of a liquid is equal to the external pressure surrounding the liquid.

On the basis of bonding, the compound which has highest boiling point is sodium chloride.

Alcohol are found to have boiling point approximately as 78.37 °C.

Glucose usually melts at 146 °C.

Water boils at 100°C.

Sodium chloride has boiling point 1413 °C.

So, it is easy to identify that NaCl (sodium chloride) has highest boiling point amongst the given choices.

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An atom is determined to contain 12 protons, 10 electrons, and 12 neutrons. What are the mass number and charge of this atom or
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7 0
4 years ago
Each day one astronaut exhales about 448 L of carbon dioxide. how many grams of LiOH is needed to remvoe this much carboon dioxi
Romashka [77]

Answer:

How to determine the mole of LiOH required to react with 20 moles of CO₂ per day

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From the balanced equation above,

1 mole of CO₂  required 2 moles of LiOH.

Therefore,

20 moles of CO₂ will require = 20 × 2 = 40 moles of LiOH

How to determine the mole of LiOH required by two astronauts for 3 days

Mole of LiOH for 1 person per day = 40 moles

Mole of LiOH for 2 persons per day = 2 × 40 = 80 moles

Mole of LiOH for 2 persons for 3 days = 80 × 3 = 240 moles

Explanation:

mark brainliest

7 0
2 years ago
A sample of argon gas (molar mass 40 g) is at four times the absolute temperature of a sample of hydrogen gas (molar mass 2 g).
katen-ka-za [31]

Answer:

Ratio of Vrms of argon to Vrms of hydrogen = 0.316 : 1

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The root-mean-square speed measures the average speed of particles in a gas, and is given by the following formula:  

Vrms = \sqrt{3RT/M}

where R is molar gas constant = 8.3145 J/K.mol, T is temperature in kelvin, M is molar mass of gas in Kg/mol

For argon, M = 40/1000 Kg/mol = 0.04 Kg/mol, T = 4T , R = R

Vrms = √(3 * R *4T)/0.04 = √300RT

For hydrogen; M = 1/1000 Kg/mol = 0.001 Kg/mol, T = T, R = R

Vrms = √(3 * R *T)/0.001 = √3000RT

Ratio of Vrms of argon to that of hydrogen = √300RT / √3000RT = 0.316

Ratio of Vrms of argon to that of hydrogen = 0.316 : 1

4 0
4 years ago
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