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attashe74 [19]
3 years ago
15

Your body uses about 24 grams of Glucose to run cellular respiration. How many molecules does your body need for cellular respir

ation?
Chemistry
1 answer:
BartSMP [9]3 years ago
6 0

Answer:

for the cellular respiration the human body needs 1.424 E21 molecules of glucose

Explanation:

mass glucose = 24 g

∴ Mw glucose = 180.156 g/mol

∴ 1 mol ≡ 6.022 E23 molecules

⇒ mol glucose = (24 g)×(mol/180.156 g) = 0.1332 mol glucose

⇒ molecules glucose = (0.1332 mol glucose)×(6.022 E23 molecules/mol)

⇒ molecules glucose = 1.424 E21 molecules

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Striped should be the answer

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Which has a greater momentum, a car or a bike moving at the same speed​
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PLZ HELP "NO LINKS"
Natalka [10]

Answer: (a) Mole fraction of H_{2} is 0.66.

Mole fraction of N_{2} is 0.33

(b) The partial pressure of H_{2} is 1.98 atm.

The partial pressure of N_{2} is 0.99 atm.

(c) The total pressure is 3.0 atm

Explanation:

Given: Volume = 22.4 dm^{3}  (1 dm^{3} = 1 L) = 22.4 L

Moles of H_{2} = 2.0 mol

Moles of N_{2} = 1.0 mol

Total moles = (2.0 + 1.0) mol = 3.0 mol

Temperature = 273.15 K

  • Now, using ideal gas equation the total pressure is calculated as follows.

PV = nRT\\

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm

  • The mole fractions of each component:

The mole fraction of H_{2} is calculated as follows.

Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66

The mole fraction of N_{2} is as follows.

Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33

  • The partial pressures of each component:

Partial pressure of H_{2} are as follows.

P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm

Partial pressure of N_{2} are as follows.

P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm

7 0
3 years ago
How much energy does cameron need to add to raise the temperature of a 0.500-kg sample of silver from 200 k to 205 k? the specif
zzz [600]

energy to raise temperature is 590 J

Given:

mass of silver sample = 0.5 kg

initial temperature = 200 k

final temperature = 205 k

specific heat of silver = 236 j/kgk

To Find:

energy to raise temperature

Solution: The heat energy required to raise the temperature of of a substance through is called its specific heat capacity.

Q = cmΔt

where c= constant of proportionality, called specific heat capacity of the body

Q = mass x specific heat x ∆t

= 0.5 x 236 x ( 205-200 )

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So, energy to raise temperature is 590 J

Learn more about Specific heat capacity here:

brainly.com/question/16559442

#SPJ4

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2 years ago
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